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lisov135 [29]
3 years ago
14

Lisa wants to build a table and put a border around it. The table and border must have an area of 3,996 square inches. The table

is 42 inches wide and 36 inches long without the border. Which quadratic equation can be used to determine the thickness of the border, x?
Mathematics
1 answer:
Vinvika [58]3 years ago
3 0

Answer:

The answer is 2,484.

Step-by-step explanation:

First you would have to multiply 42 times 36 then subtract 1,512 from 3,996 you will get 2,484

You might be interested in
The graphs of the quadratic functions f(x) = 6 – 10x2 and g(x) = 8 – (x – 2)2 are provided below. Observe there are TWO lines si
natta225 [31]

Answer:

a) y = 7.74*x + 7.5

b)  y = 1.148*x + 6.036

Step-by-step explanation:

Given:

                                  f(x) = 6 - 10*x^2

                                  g(x) = 8 - (x-2)^2

Find:

(a) The line simultaneously tangent to both graphs having the LARGEST slope has equation

(b) The other line simultaneously tangent to both graphs has equation,

Solution:

- Find the derivatives of the two functions given:

                                f'(x) = -20*x

                                g'(x) = -2*(x-2)

- Since, the derivative of both function depends on the x coordinate. We will choose a point x_o which is common for both the functions f(x) and g(x). Point: ( x_o , g(x_o)) Hence,

                                g'(x_o) = -2*(x_o -2)

- Now compute the gradient of a line tangent to both graphs at point (x_o , g(x_o) ) on g(x) graph and point ( x , f(x) ) on function f(x):

                                m = (g(x_o) - f(x)) / (x_o - x)

                                m = (8 - (x_o-2)^2 - 6 + 10*x^2) / (x_o - x)

                                m = (8 - (x_o^2 - 4*x_o + 4) - 6 + 10*x^2)/(x_o - x)

                                m = ( 8 - x_o^2 + 4*x_o -4 -6 +10*x^2) /(x_o - x)

                                m = ( -2 - x_o^2 + 4*x_o + 10*x^2) /(x_o - x)

- Now the gradient of the line computed from a point on each graph m must be equal to the derivatives computed earlier for each function:

                                m = f'(x) = g'(x_o)

- We will develop the first expression:

                                m = f'(x)

                                ( -2 - x_o^2 + 4*x_o + 10*x^2) /(x_o - x) = -20*x

Eq 1.                          (-2 - x_o^2 + 4*x_o + 10*x^2) = -20*x*x_o + 20*x^2

And,

                              m = g'(x_o)

                              ( -2 - x_o^2 + 4*x_o + 10*x^2) /(x_o - x) = -20*x

                              -2 - x_o^2 + 4*x_o + 10*x^2 = -2(x_o - 2)(x_o - x)

Eq 2                       -2 - x_o^2 + 4*x_o+ 10*x^2 = -2(x_o^2 - x_o*(x + 2) + 2*x)

- Now subtract the two equations (Eq 1 - Eq 2):

                              -20*x*x_o + 20*x^2 + 2*x_o^2 - 2*x_o*(x + 2) + 4*x = 0

                              -22*x*x_o + 20*x^2 + 2*x_o^2 - 4*x_o + 4*x = 0

- Form factors:       20*x^2 - 20*x*x_o - 2*x*x_o + 2*x_o^2 - 4*x_o + 4*x = 0

                              20*x*(x - x_o) - 2*x_o*(x - x_o) + 4*(x - x_o) = 0

                               (x - x_o)(20*x - 2*x_o + 4) = 0  

                               x = x_o   ,     x_o = 10x + 2    

- For x_o = 10x + 2  ,

                               (g(10*x + 2) - f(x))/(10*x + 2 - x) = -20*x

                                (8 - 100*x^2 - 6 + 10*x^2)/(9*x + 2) = -20*x

                                (-90*x^2 + 2) = -180*x^2 - 40*x

                                90*x^2 + 40*x + 2 = 0  

- Solve the quadratic equation above:

                                 x = -0.0574, -0.387      

- Largest slope is at x = -0.387 where equation of line is:

                                  y - 4.502 = -20*(-0.387)*(x + 0.387)

                                  y = 7.74*x + 7.5          

- Other tangent line:

                                  y - 5.97 = 1.148*(x + 0.0574)

                                  y = 1.148*x + 6.036

6 0
3 years ago
Help me please this is so hard
maxonik [38]

Answer: D. 136in^2

Step-by-step explanation:

Find the surface area if all sides and add

4*10=40

2*4=8

2*4=8

4*10=40

2*10=20

2*10=20

40+40+8+8+20+20=136

136in^2

3 0
3 years ago
If m∠5 =53° and m∠7 =125° , find the measures of each numbered angle.Then explain how u found each angle,citing definitions and
bija089 [108]
#5 = 53° #7 = 125° #6 = 55° #2 = 72° #3 = 55° #1 = 53° #4 = 127°

triangle = 180°
alternating interior angles are the same (#6 & #3 and #5 and #1)
#3 and #7 should equal 180°
#1 and #4 should also equal 180°
#6 and #7 should equal 180°
#4 and #5 should equal 180°
4 0
3 years ago
I need more help I dont understand these letters and numbers​
svetlana [45]

Answer:

Width also known as (W) = 1.5 meters

Area also known as (A) = 6 square meters

Length also known as (L) = ?

the formula to find Length is:

Step-by-step explanation:

L=\frac{A}{W}

L = \frac{6}{1.5}

L= 4 m

Choice 3 is the answer

1.5x = 6

x=4

substitute 4 for the x

1.5(4)=6

1.5×4 = 6

so

6=6

so the answer is

1.5x=6

x=4

8 0
3 years ago
Read 2 more answers
30 points available will give brainliest plz helpp need soon<br>i need it quick
bezimeni [28]

Answer:

90

hope it's helpful

THANK YOU.

4 0
3 years ago
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