Find the perimeter and area of the figure below.

Mathematics

1 answer:

Nuetrik [128]3 years ago

4 0

Answer: perimeter= 40

Area= 46

Step-by-step explanation:

You might be interested in

Roger bought 4 bowls at a store if each bowl cost $1.60 and he paid with a twenty dollar bill how much change should he get back

enot [183]

Answer:

$16.60 Would Be His Change

Step-by-step explanation:

Using A Calculator

3 0

3 years ago

Read 2 more answers

How to solve the equation

motikmotik

Answer: c

given volume is 125 cc

cube root of 125 is 5

aka 5×5×5=125

and 6×5×5=150

hence answer is c

5 0

3 years ago

How do I andser this. I’m stuck

Mars2501 [29]

A= 3:5
b= 12:20
c= yes because 3” 3+2=5 n in the beginning of the problem it said end of season

8 0

3 years ago

Three security cameras were mounted at the corners of a triangles parking lot. Camera 1 was 110 ft from camera 2, which was 137

Nata [24]

Answer:

<em>Camera 2nd has to cover the maximum angle, i.e. </em> $78.70^\circ$ .

Step-by-step explanation:

Please have a look at the triangular park represented as a triangle $\triangle ABC$ with sides

a = 110 ft

b = 158 ft

c = 137 ft

1st camera is located at point C, 2nd camera at point B and 3rd camera at point A respectively.

We can use law of cosines here, to find out the angles $\angle A, \angle B, \angle C$

As per Law of cosine:

$cos C = \dfrac{a^{2}+b^2-c^2 }{2ab}\\cos B = \dfrac{a^{2}+c^2-b^2 }{2ac}\\cos A = \dfrac{b^{2}+c^2-a^2 }{2bc}$

Putting the values of a,b and c to find out angles $\angle A, \angle B, \angle C$ .

$cos C = \dfrac{110^{2}+158^2-137^2 }{2\times 110 \times 158}\\\Rightarrow cos C = \dfrac{12100+24964-18769 }{24760}\\\Rightarrow cos C =0.526\\\Rightarrow C = 58.24^\circ$

$cos B = \dfrac{110^{2}+137^2-158^2 }{2\times 110 \times 137}\\\Rightarrow cos B = \dfrac{12100+18769 -24964}{30140}\\\Rightarrow cos B = \dfrac{5905}{30140}\\\Rightarrow cos B =0.196\\\Rightarrow B = 78.70^\circ$

$cos A = \dfrac{158^{2}+137^2-110^2 }{2\times 158 \times 137}\\\Rightarrow cos A = \dfrac{24964+18769-12100}{43292}\\\Rightarrow cos A = \dfrac{31633}{43292}\\\Rightarrow cos A = 0.731\\\Rightarrow A = 43.05^\circ$