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Verizon [17]
3 years ago
15

What is 1/2 x (8x4+6) + 11pls help

Mathematics
1 answer:
Novosadov [1.4K]3 years ago
5 0

Answer:

30

Step-by-step explanation:

But it's only if your simplifying

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Unit rate is miles per 1 gallon
50mi/2 and 1/2 gallon
50mi/2.5 gallon
times 10/10
500mi/25 gallon
20mi/1gallon

answer is 20mi/gal
6 0
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There are 10 rolls of film in a box and 3 are defective. two rolls are selected without replacement. what is the probability of
german

P(picking one defective) = 3/10
P(picking a 2nd defective) = 2/9


P(1 and 2  defective) = 3/10 x 2/9  = 6/90 = 0.066

Second method using combination:
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4 0
3 years ago
Find the measure of the ndicaited angle to the nearest degree 35 and 38
12345 [234]

The measure of the indicated angle to the nearest degrees is 23 degrees.

<h3>How to find angle of a right angle triangle?</h3>

The angle of a right angle triangle can be found as follows:

Therefore, the angle can be found using trigonometric ratios as follows;

cos ∅ = adjacent / hypotenuse

Therefore,

adjacent side = 35 units

hypotenuse side = 38 units

Hence,

cos ∅ = 35 / 38

∅ = cos⁻¹ 0.92105263157

∅ = 22.9272842944

∅ ≈ 23 degrees.

learn more on triangle here: brainly.com/question/20759265

#SPJ1

6 0
1 year ago
Sofia's poster is 0.75 meter long. Rafael's poster is 0.35 meter less than 1 meter long. Which expression shows the difference i
Nady [450]
0.75 - (1-0.35) or 0.75 - 1 + 0.35
5 0
3 years ago
1 The prism-shaped roof has equilateral triangular bases. Use the model you created in question #1 to calculate the height of th
Diano4ka-milaya [45]

Answer:

Step-by-step explanation:

Step-by-step explanation:  As shown in the attached figure, the prism-shaped roof has equilateral triangular bases, one of which is ΔABC. We need to create an equation that models the height of one of the roof's triangular bases in terms of its sides. Let ii be AD.

See the figure attached herewith, ΔABC forms an equilateral triangle, in which AD is the height. So, D will be the mid-point of BC and ∠ADB = ∠ADC = 90°.

Now, in ΔADB, we have

AD^2=AB^2-BD^2

AD^2=AB^2-(1/2AB^2)^2

AD=√3/4AB^2

we can find the height of any one of the roof's triangular bases.

2.1. Check picture 1. Let the one side of the triangle be a, drop one perpendicular, CD. Then triangle ADB is a right triangle, with hypothenuse a and one side equal to 1/2a. By the Pythagorean theorem, as shown in the picture, the height is √3/2a

2. if a=25 ft, then the height is  √3/2a=√3/2*25=1.732/2*25=21.7(ft)

3. consider picture 2. Let the length of the roof be l feet.

one side of the prism (the roof) is a rectangle with dimensions a and l, so the area of one side is a*l

the lateral Area of the roof is 3a*l

the area of the equilateral surfaces is 2*(1/2*a*√3/2a)=√3/2a^2  

so the total area of the roof is  

4. The total area was the 2 triangular surfaces + the 3 equal lateral rectangular surfaces. Now instead of 3 lateral triangular surfaces, we have 2.

So the total area found previously will be decreased by al

5. so the area now is √3/2a^2 + 2al  

6. now a=25 and l=2a=50

Area= √3/2a^2+2al=√3/2*25^2+2*25*50=25^2(√3/2+4)=625*4.866

=3041.3 (ft squared)

6 0
3 years ago
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