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mariarad [96]
3 years ago
15

Gcf of 28 and84 and 65 39 and 75 and 45

Mathematics
1 answer:
Stells [14]3 years ago
6 0
I hope this helps you

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Help ill mark you brainlist
adell [148]
The differences between he numbers are 19, so the answer is 58 + 19 = 71
8 0
3 years ago
What is the solution to the equation?
KonstantinChe [14]
Answer: D
1/2x-1+4=x
1/2x-x=-3
-1/2x=-3
x=6
4 0
3 years ago
Read 2 more answers
SOLVE ALL THESE EQUATION BY USING THE METHOD SUBSTITUTION ALGEBRAICALLY HERE'S ARE ALL THE EQUATION:
pav-90 [236]

Answer:

See below ~

Step-by-step explanation:

<u>Question 1</u>

  • -7x - y = -1
  • y = 8x + 16

⇒ -7x - (8x + 16) = -1

⇒ -7x - 8x - 16 = -1

⇒ -15x = 15

⇒ x = -1

⇒ y = 8(-1) + 16 = 8

⇒ Solution = <u>(-1, 8)</u>

<u></u>

<u>Question 2</u>

  • 3x + 4y = 0
  • y = -3x - 18

⇒ 3x + 4(-3x - 18) = 0

⇒ 3x - 12x - 72 = 0

⇒ -9x = 72

⇒ x = -8

⇒ y = -3(-8) - 18 = 6

⇒ Solution = <u>(-8, 6)</u>

<u>Question 3</u> (not clear)

<u>Question 4</u>

  • -8x - 7y = 0
  • y = 6x

⇒ -8x - 7(6x) = 0

⇒ -8x - 42x = 0

⇒ -50x = 0

⇒ x = 0

⇒ y = 6(0) = 0

⇒ Solution = <u>(0, 0)</u>

<u>Question 8</u>

  • 2x - 6y = -14
  • y = -5x - 19

⇒ 2x - 6(-5x - 19) = -14

⇒ 2x + 30x + 114 = -14

⇒ 32x = -128

⇒ x = -4

⇒ y = -5(-4) - 19 = 1

⇒ Solution = <u>(-4, 1)</u>

3 0
2 years ago
Find lim h 0 f(2+h)-f(2)/ h if(x)=x^ 2 .
jonny [76]

Answer:

4

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Eric was rock climbing. At one point, he stopped and climbed straight down 2\dfrac{1}{2}2
nikitadnepr [17]

The equation that matches the given situation is -2\frac{1}{2}+6\frac{3}{4}=? . So, after two moves, Eric's elevation changed 4\frac{1}{4} meters above.

We know that in mathematics, subtraction means removing something from a group or a number of things. What is left in the group gets smaller when we subtract. The minuend is the first element we use. The subtrahend is the part that is being removed. The difference is the portion that remains after subtraction.

Assume that "negative" means climbing down and "positive" means climbing up. We must locate the elevation change in this area.

Given that Eric climbed straight down 2\frac{1}{2} meters. So we can write -2\frac{1}{2}.

Again Eric climbed straight up 6\frac{3}{4} meters. So, we can write 6\frac{3}{4}.

Then the change = -2\frac{1}{2}+6\frac{3}{4}

=-\frac{(2*2+1)}{2}+\frac{6*4+3}{4}

=-\frac{5}{2} +\frac{27}{4}

=\frac{-(5*2)+27}{4}

=\frac{-10+27}{4}

=\frac{17}{4}

=\frac{4*4+1}{4}

=4\frac{1}{4}

Therefore, the equation that matches the given situation is -2\frac{1}{2}+6\frac{3}{4}=? . So, after two moves, Eric's elevation changed 4\frac{1}{4} meters above.

Learn more about subtraction here -

brainly.com/question/24116578

#SPJ10

7 0
1 year ago
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