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astraxan [27]
3 years ago
12

A girl has 11 coins in dimes and quarters. Their value is $1.55. How many quarters does she have?

Mathematics
1 answer:
igomit [66]3 years ago
3 0

Answer:

3

Step-by-step explanation:

pretty simple if she has 8 it wouldnt make sense

5 that means shell have 6 simed with $1.25 worth of money

sooooooooo yeah

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dedylja [7]

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Step-by-step explanation:

7 0
3 years ago
Given f(x) = 5x - 6 and g(x) = x2 - 5x + 6, find the function (f + g)(x). Use the ^ key for the exponent. Enter your answer as t
sesenic [268]
The answer is x².

f(x) = <span>5x - 6
</span>g(x) = x²<span> - 5x + 6

(f + g)(x) = f(x) + g(x)
              = </span>5x - 6 + x² - 5x + 6
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6 0
4 years ago
I need help with this
andre [41]

Answer:

  f(x)=\dfrac{(x+3)(x-1)^2}{(x+4)(x+3)(x-2)^2}

Step-by-step explanation:

Each vertical asymptote corresponds to a zero in the denominator. When the function does not change sign from one side of the asymptote to the other, the factor has even degree. The vertical asymptote at x=-4 corresponds to a denominator factor of (x+4). The one at x=2 corresponds to a denominator factor of (x-2)², because the function does not change sign there.

__

Each zero corresponds to a numerator factor that is zero at that point. Again, if the sign doesn't change either side of that zero, then the factor has even multiplicity. The zero at x=1 corresponds to a numerator factor of (x-1)².

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Each "hole" in the function corresponds to numerator and denominator factors that are equal and both zero at that point. The hole at x=-3 corresponds to numerator and denominator factors of (x-3).

__

Taken altogether, these factors give us the function ...

  \boxed{f(x)=\dfrac{(x+3)(x-1)^2}{(x+4)(x+3)(x-2)^2}}

8 0
3 years ago
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