Question

∠X=5x+30 ∘ ​ \angle \mathrm{Y}=3\mathrm{x}+60^{\circ}∠Y=3x+60 ∘

Answer 1

Corresponding angles on parallel lines cut by a transversal are equal

5x + 30 = 3x + 60

Subtract 3x from both sides

2x + 30 = 60

Subtract 30 from both sides

2x = 30

Divide both sides by 2

X = 15

Answer 2

ANSWER:

We know that, Corresponding angles on parallel line cut by a transversal are equal.

So, ∠X = ∠Y

• 5x + 30° = 3x + 60°
• 5x – 3x = 60° – 30°
• 2x = 30°
• x = 30/2
• x = 15°

Hence, the value of x is 15 degree.