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4vir4ik [10]
3 years ago
15

Sample A: 300 mL of 1M sodium chloride

Chemistry
1 answer:
pantera1 [17]3 years ago
6 0

Answer:

Sample A

Explanation:

Molarity of a solution can be calculated using the formula:

Molarity = number of moles (mol) ÷ volume (vol)

For Sample A:

V = 300ml = 300/1000 = 0.3 L

Molarity = 1M

n = number of moles (mol)

1 = n/0.3

n = 0.3moles

For Sample B:

V = 145 mL = 145/1000 = 0.145L

Molarity = 1.5 M

n = number of moles

1.5 = n/0.145

n = 1.5 × 0.145

n = 0.22 moles

Based on the above results (moles), sample A with 0.3 moles contains the larger concentration of sodium chloride.

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How many moles of copper are present in a sample of tennantite with a mass of 2290 grams?
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Answer:

               18.58 moles of Cu

Solution:

Data Given:

                  Chemical Formula of Tennantite  =  Cu₁₂As₄S₁₃

                  Mass of Cu₁₂As₄S₁₃  =  2290 g

                  M.Mass of Cu₁₂As₄S₁₃  =  1479.06 g.mol⁻¹

Step 1: Calculate Moles of Cu₁₂As₄S₁₃ as,

                               Moles  =  Mass ÷ M.Mass

Putting values,

                               Moles  =  2290 g ÷ 1479.06 g.mol⁻¹

                                Moles  =  1.548 mol

Step 2: Calculate Moles of Cu,

As,

                         1 mole of Cu₁₂As₄S₁₃ contains  =  12 moles of Cu

So,

               1.548 mol of Cu₁₂As₄S₁₃ will contain  =  X moles of Cu

Solving for X,

                     X  =  (1.548 mol × 12 mol) ÷ 1 mol

                     X  =  18.58 moles of Cu

5 0
4 years ago
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