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umka2103 [35]
3 years ago
12

The density of silver is 10.5 g/cm3. what would be the mass (in grams) of a piece of silver that occupies a volume of 23.6 cm3?

Chemistry
2 answers:
rjkz [21]3 years ago
8 0

Answer:

Mass, m = 247.8 grams

Explanation:

It is given that,

Density of silver, d=10.5\ g/cm^3

Volume occupies by the silver, V=23.6\ cm^3

We need to find the mass of a piece of silver. The formula for the density is given by :

d=\dfrac{m}{V}

m=d\times V

m=10.5\times 23.6

m = 247.8 g

So, the mass of the piece of the silver is 247.8 grams. Hence, this is the required solution.

Keith_Richards [23]3 years ago
6 0
Hey there : !

density = 10.5 g/cm³

volume = 23.6 cm³

therefore:

D = m / V

10.5 = m / 23.6

m = 10.5 * 23.6

m = 247.8 g

hope this helps!
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Answer:

induced dipole-dipole forces or London Dispersion forces / van der Waals forces.

Explanation:

Hexane is non-polar in nature. This is due to :

The bond in the molecule is C-H, which is non-polar in nature because the carbon and the hydrogen having very similar electronegativity values.

Hexane is also symmetric.

The intermolecular force acting in the molecule of the hexane are induced the dipole-dipole forces or London Dispersion forces / van der Waals forces.

7 0
3 years ago
How many milliliters of 2.19 M H2SO4 are required to react with 4.75 g of solid containing 21.6 wt% Ba(NO3)2 if the reaction is
Setler [38]

Answer:

1.7927 mL

Explanation:

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This solid contains 21.6 wt% Ba(NO_3)_2, thus,

Mass of Ba(NO_3)_2 = \frac {21.6}{100}\times 4.75\ g = 1.026 g

Molar mass of Ba(NO_3)_2 = 261.337 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{1.026\ g}{261.337\ g/mol}

Moles= 0.003926\ mol

Considering the reaction as:

Ba(NO_3)_2+H_2SO_4\rightarrow BaSO_4+2HNO_3

1 moles of Ba(NO_3)_2 react with 1 mole of H_2SO_4

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0.003926 mole of Ba(NO_3)_2 react with 0.003926 mole of H_2SO_4

Moles of H_2SO_4 = 0.003926 mole

Also, considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

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2.19=\frac{0.003926}{Volume\ of\ the\ solution(L)}

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I found the attached image with the same statement of your question and think it may be very useful for you that I use it to show how to answer this question (furthermore I think it may be the same reaction that you forgot to include).

As you can see, there are one image on the left side and other image on hte right side of the figure.

Those images contains drawings that represent molecules and a legend that permit you to distinguish the kind of atoms in each molecule.

Using that, you can indicate the chemical reaction as the transformation of the molecules on the left side onto the molecules on the right side:

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3 molecules of CH4 and 3 molecules of N2Cl4

Right side:

3 molecules of CCl4, 3 molecules of N2 and 6 molecules of H2

That is represented as:

3CH4 + 3 N2Cl4 -----> 3 CCl4 + 3N2 + 6H2

And that is the balanced chemical equation for the reaction shown in the figured attached.

I hope this is useful for you..






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irina1246 [14]

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