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2 years ago

The density of silver is 10.5 g/cm3. what would be the mass (in grams) of a piece of silver that occupies a volume of 23.6 cm3?

Chemistry

2 answers:

rjkz [21]2 years ago

8 0

Answer:

Mass, m = 247.8 grams

Explanation:

It is given that,

Density of silver, $d=10.5\ g/cm^3$

Volume occupies by the silver, $V=23.6\ cm^3$

We need to find the mass of a piece of silver. The formula for the density is given by :

$d=\dfrac{m}{V}$

$m=d\times V$

$m=10.5\times 23.6$

m = 247.8 g

So, the mass of the piece of the silver is 247.8 grams. Hence, this is the required solution.

Keith_Richards [23]2 years ago

6 0

Hey there : !

density = 10.5 g/cm³

volume = 23.6 cm³

therefore:

D = m / V

10.5 = m / 23.6

m = 10.5 * 23.6

m = 247.8 g

hope this helps!

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How many grams of solid NaOH are required to prepare a 400ml of a 5N solution? show your work!

Nuetrik [128]

Answer: The mass of solid NaOH required is 80 g

Explanation:

Equivalent weight is calculated by dividing the molecular weight by n factor. The equation used is:

$\text{Equivalent weight}=\frac{\text{Molecular weight}}{n}$

where,

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Putting values in above equation, we get:

$\text{Equivalent weight}=\frac{40g/mol}{1eq/mol}=40g/eq$

Normality is defined as the umber of gram equivalents dissolved per liter of the solution.

Mathematically,

$\text{Normality of solution}=\frac{\text{Number of gram equivalents} \times 1000}{\text{Volume of solution (in mL)}}$

Or,

$\text{Normality of solution}=\frac{\text{Given mass}\times 1000}{\text{Equivalent mass}\times \text{Volume of solution (in mL)}}$ ......(1)

We are given:

Given mass of NaOH = ?

Equivalent mass of NaOH = 40 g/eq

Volume of solution = 400 mL

Normality of solution = 5 eq/L

Putting values in equation 1, we get:

$5eq/L=\frac{\text{Mass of NaOH}\times 1000}{40g/eq\times 400mL}\\\\\text{Mass of NaOH}=80g$

Hence, the mass of solid NaOH required is 80 g

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Answer:

$\large \boxed{\text{4.63 atm}}$

Explanation:

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Data:

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