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3 years ago

An equestrian club orders magazine subscriptions for new members.

Mathematics

2 answers:

Margarita [4]3 years ago

8 0

Answer: $19.16

Step-by-step explanation:

for this problem, you will need to divide 624 by 32. first, you line them up. then, you find out how many times 32 will go into 62. 32 will go into 62 once, so write a one in the tens column, since 32 could not go into 6. next, you subtract 32 from 62, and get 30. now, you bring down the four. your new number is 304. 32 can go into 304 9 times, and get 288. now, you subtract 288 from 304 and get 16, making your answer 19.16.

lukranit [14]3 years ago

5 0

Answer: The cost for each subscription is $19.5

Step-by-step explanation:

32m=624

Divide 32 on both sides:

32m/32=624/32

m=19.5

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I need help with this question

creativ13 [48]

The 2nd option from the top

5 0

4 years ago

To estimate the mean height μ of male students on your campus,you will measure an SRS of students. You know from government data

nexus9112 [7]

Answer:

a) $\sigma = 0.167$

b) We need a sample of at least 282 young men.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

This Zscore is how many standard deviations the value of the measure X is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

(a) What standard deviation must x have so that 99.7% of allsamples give an x within one-half inch of μ?

To solve this problem, we use the 68-95-99.7 rule. This rule states that:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviations of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we want 99.7% of all samples give X within one-half inch of $\mu$ . So $X - \mu = 0.5$ must have $Z = 3$ and $X - \mu = -0.5$ must have $Z = -3$ .

$Z = \frac{X - \mu}{\sigma}$

$3 = \frac{0.5}{\sigma}$

$3\sigma = 0.5$

$\sigma = \frac{0.5}{3}$

$\sigma = 0.167$

(b) How large an SRS do you need to reduce the standard deviationof x to the value you found in part (a)?

You know from government data that heights of young men are approximately Normal with standard deviation about 2.8 inches. This means that $\sigma = 2.8$