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2 years ago

Tires are rotating at a rate of 35 revolutions per minute. Find the angular speed of the tires in radians per minute.

Mathematics

1 answer:

Alexxx [7]2 years ago

7 0

Answer:

35poi

Step-by-step explanation:

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Expanded form of<br>a 54896<br>

borishaifa [10]

Answer:

50000 4000 800 90 6

Step-by-step explanation:

there is the answer.

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2 years ago

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Vlada [557]

Answer:

-1,3,5,9is a required answer.

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3 years ago

A rectangular painting by Leonardo da Vinci measured 62cm along its diagonal. If the painting has a height of 42 cm how wide is

IRINA_888 [86]

ANSWER

45.6cm to the nearest tenth.

EXPLANATION

The diagonal of the rectangular painting is 62cm.

The height of the painting is 42 cm.

The height of the painting h , the diagonal, and the width of the painting forms a right triangle with the diagonal being the hypotenuse.

From the Pythagoras Theorem,

${w}^{2} + {42}^{2} = {62}^{2}$

${w}^{2} = {62}^{2} - {42}^{2}$

${w}^{2} = 2080$

${w} = \sqrt{2080}$

$w = 4 \sqrt{130}$

The width of the painting is 45.6cm to the nearest tenth.

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3 years ago

Mr anderson wrote 7 times 9 times 10 on the board what is the value of that expression

yaroslaw [1]

630

Hope this helps. :D

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3 years ago

In the adjoining figure, XY = XZ . YQ and ZP are the bisectors of <img src="https://tex.z-dn.net/?f=%20%5Cangle" id="TexFormula1

svetlana [45]

Answer:

See Below.

Step-by-step explanation:

Statements: Reasons:

$1)\, XY=XZ$ Given

$2) \text{ $ m\angle Y= m\angle Z$}$ Isosceles Triangle Theorem

$\displaystyle 3) \text{ $m\angle Y=m\angle XYQ + \angle QYZ$}$ Angle Addition

$\displaystyle 4)\text{ $YQ$ bisects $\angle XYZ$}$ Given

$5) \text{ $m\angle XYQ=m\angle QYZ$}$ Definition of Bisector

$\displaystyle 6)\text{ $m\angle Y=2m\angle QYZ$}$ Substitution

$7)\text{ $m\angle Z=m\angle XZP+m\angle PZY$}$ Angle Addition

$8)\text{ $ZP$ bisects $\angle XZY$}$ Given

$\displaystyle 9) \text{ $m\angle XZP=m\angle PZY$ }$ Definition of Bisector

$\displaystyle 10) \text{ $ m\angle Z = 2m\angle PZY $}$ Substitution

$11)\text{ } 2m\angle QYZ=2m\angle PZY$ Substitution

$12)\text{ }m\angle QYZ=m\angle PZY$ Division Property of Equality

$13)\text{ } YZ=YZ$ Reflexive Property

$14)\text{ } \Delta YZP\cong\Delta ZYQ$ Angle-Side-Angle Congruence*

$15)\text{ } YQ=ZP$ CPCTC

*For clarification:

∠Y = ∠Z

YZ = YZ (or ZY)

∠PZY = ∠QYZ

So, Angle-Side-Angle Congruence:

ΔYZP is congruent to ΔZYQ

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2 years ago

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