It is not recommended that points be marked with X, let's marked with C(6,6)=(Xc,Yc)
The coordinates of the point C(Xc,Yc) which belongs to the line AB and divides line AB in a ratio m : n = 1 : 2 or m/n=1/2 are get it with following formula
Xc=(Xa+(m/n)Xb) / (1+(m/n)) and Yc=(Ya+(m/n)Yb) / (1+(m/n))
We have A(2,2)=(Xa,Ya) and B(14,14)=(Xb,Yb)
When we replace given coordinates we get
Xc=(2+(1/2)*14) / (1+(1/2)) = (2+7) /(3/2) = 9/(3/2) = (9*2)/3 = 3*2 =6 => Xc=6
Yc=(2+(1/2)*14) / (1+(1/2)) = (2+7) / (3/2) = 9/(3/2) = (9*2)/3 = 3*2 =6 => Yc=6
C(Xc,Yc)=(6,6)
Good luck!!!
9514 1404 393
Answer:
36
Step-by-step explanation:
The parallel lines divide the segments proportionally.
GH/HI = GK/KJ
GH = HI(GK/KJ) = 48(30/40)
GH = 36
Answer:
x = 10
Step-by-step explanation:
The total length of segment PS is 52. To solve for x, we can simply add 5x (which is the length of segment PR) and x-8 (which is the length of segment RS) together and make the equation equal to 52 to solve for x.
- 5x+x-8 = 52
- 6x - 8 = 52
- 6x = 60
- x = 10