f(x) = log2 x
f(40) = log2 40
40 = 2^y
2^5 = 32 and 2^6 = 64
so f(40) lies between integers 5 and 6.
Answer:
x = {-4, 4}
Step-by-step explanation:
Subtracting 3 gives ...
5x^2 = 80
Dividing by 5, we get ...
x^2 = 16
Taking the square root gives the solutions ...
x = ±4
The smaller value of x is -4; the larger value is 4.
Answer:
Step-by-step explanation:
6n < -12
6n/6 <-12/6 divide six on both sides
n < -2
Answer:
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Step-by-step explanation:
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