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Mama L [17]
3 years ago
10

PLSS HELP MEEEEEEE PLSSS

Mathematics
1 answer:
grigory [225]3 years ago
4 0
2(3.14)6x12+2(3.14)(6)^2
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A machine paints 340 toy boats in 45 minutes.Which expression equals the rate per hour?
Elenna [48]

Answer:

The expression for rate per hour is \frac{340}{45}\times 60.

Explanation:

Given:

A machine paints 340 toy boats in 45 minutes.

To Find:

Expression equals the rate per hour?

Solution:

Finding the expression for rate per minute:

\text{{The rate per minute expression}} =\frac{\text{{ (number of toys painted in time given)}}}{\text{{(number of minutes taken)}}}

So, rate per minute expression is \frac{(340 toys)}{(45 minutes)} = \frac{340}{45}

Then, rate per hour expression \text{{rate per minute}}\times 60 minutes

So, rate per hour expression is \frac{340}{45}\times60 minutes= 453.334 toys per hour.

Hence, the expression for rate per hour is \frac{340}{45}\times 60

8 0
3 years ago
todd curently has 5,000 what was the value of his money four years ago if hes earned 4% interest each year
coldgirl [10]
A(t)  = P (1+rt)

5000 = P ( 1 + 0.04 *4)

5000 = P (1.16)

P = 4310.34
6 0
4 years ago
Read 2 more answers
10 times as many as 1 hundred is _____ hundreds or________ thousand.
Alchen [17]
So if 10 times then 48=23
5 0
4 years ago
Read 2 more answers
30 in
allsm [11]
Just add them all up that’s it and you will get 20
8 0
3 years ago
A random sample of 16 ATM transactions at the Last National Bank of Flat Rock revealed a mean transaction time of 2.8 minutes wi
ddd [48]

The width (in minutes) of the 95 percent confidence interval for the true mean transaction time is <u>1.2786 minutes</u>.

Sample size (n) = 16.

Sample mean = 2.8 minutes.

Sample standard deviation (σ) = 1.2 minutes.

Confidence interval given = 95%.

The degree of freedom (df) can be calculated as n - 1.

df = n - 1 = 16 - 1 = 15.

Since, the level of confidence is 95%, the level of significance α = 1 - 0.95 = 0.05.

From the T-Distribution table, we take the value at critical value α/2 with the degree of freedom 15.

t_{\frac{\alpha }{2} ,15} = 2.131.

Now, the margin of error can be shown as follows:

E = t_{\frac{\alpha }{2} ,15} * \frac{\sigma}{\sqrt{n} } \\\Rightarrow E = 2.131 * \frac{1.2}{\sqrt{16} }\\ \Rightarrow E = 0.6393

The width at the confidence interval of 95%, is twice the margin of error, that is:

Width = 2*E = 2*0.6393 = 1.2786.

Thus, the width (in minutes) of the 95 percent confidence interval for the true mean transaction time is <u>1.2786 minutes</u>.

Learn more about the width of distribution at

brainly.com/question/19338886

#SPJ4

6 0
2 years ago
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