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Alja [10]
4 years ago
13

How many values of θ will satisfy tan-1 0 = θ when 0º<θ<90º?

Mathematics
1 answer:
Ber [7]4 years ago
8 0
We want to satisfy
tan⁻¹ 0 = θ when 0° < θ < 90°.

The restriction on θ places the angle in the 1st quadrant.
When tan θ = 0, θ = 0°, 180°, 360°, ...
If θ >= 0, then a solution exists in the 1st quadrant.
Because of the requirement θ>0, no answer satisfies the given equation.

Answer: None

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The teacher chose option 2, the Starfish and it was valued at $35,200 after two months.

Step-by-step explanation:

Step 1; The Zoomba is priced at $60,000 and has an expected depreciation of 2% per month. So the annual depreciation is 12 months * 2% per month = 24% per year. The teacher plans to keep either car for two years do total depreciation is 2 years * 24% depreciation per year = 48 % in two years.

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The car will be valued at $31,200 after two years. To determine how much value it has retained we divide the value in two years to the current value i.e $31,200 divided by $60,000 which equals 0.52 (52% of initial price)

Step 2; The Starfish is priced at $40,00 and will depreciate $200 every month. For a year it will depreciate 12 months * $200 per month = $2,400 a year. So for a total of two years a depreciaition of $4,800.

Value of car after two years = Buying price - Depreciation amount

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The car will be valued at $35,200 after two years. To see the retained value we divide the depreciated value by the current value i.e. $35,200 divided by $40,000 which equals 0.88 (88% of the initial price)

Step 3; Of the two options, the Starfish retains more of its value over two years. So the teacher chose the Starfish over the Zoomba.

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Step-by-step explanation:

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Applying the quotient derivative formula

C'(t) = \frac{(100t)'(t^{2} + 25) - (t^{2} + 25)'(100t)}{(t^{2} + 25)^{2}}

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