Answer:

If we multiply by cross we got:

We can divide both sides of the last equation by
and we got:

And if we apply arcsin in both sides we got:

And the best solution would be:
C) pi/2
Step-by-step explanation:
For this case we want to solve the following equation:

And we know that by definition 
And replacing we got:

If we multiply by cross we got:

We can divide both sides of the last equation by
and we got:

And if we apply arcsin in both sides we got:

And the best solution would be:
C) pi/2