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Nataly_w [17]
3 years ago
13

How are cirrocumulus clouds formed?

Chemistry
1 answer:
fomenos3 years ago
7 0
Water is evaporated into the atmosphere and clouds are formed
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a sample of gas initially at 0.92 atm and a temperature of 23.2 oc is heated to 40.1 oc. the resulting pressure is 1.3 atm which
Sliva [168]

From the gas law, PV=nRT we can say that P(pressure), V(volume) and T (temperature) are related to each other. The initial volume of sample is 408 ml

Given that initial volume of the sample = V1

initial pressure of the sample = 0.92atm

initial temperature of the sample = 23.2oC

Final pressure of the sample = 1.3atm

Final  temperature of the sample = 40.1 oC

Final  volume of the sample = 500ml = 0.5L

Using the relation P1V1/T1 = P2V2/T2

V1 = 1.3x0.5x23.2/40.1x0.92 = 15.08/36.892 = 0.408

Hence the initial volume of sample = 408 ml

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6 0
2 years ago
Who was the first person to suggest the existence
katrin2010 [14]

Answer:

democritus is the first person

3 0
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What do you think would happen if you had a very small amount of water in a glass and you filled the glass with salt? Would the
Ugo [173]
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6 0
4 years ago
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A mixture of 10 moles of A, 5 moles of B and 15 moles of C is placed in a one liter container at a constant temperature. The rea
Cloud [144]

Answer:

Equilibrium constant is 0.0873

Explanation:

For the reaction:

A + B ⇄ C

Equilibrium constant is defined as:

K = [C] / [A] [B]

concentrations in equilibrium of each reactant are:

[A] = 10 - X

[B] = 5 - X

[C] = 15 + X

If concentration in equilibrium of B is 9, X is:

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Replacing:

[A] = 10 - (-4) = 14

[B] = 5 - (-4) = 9

[C] = 15 + (-4) = 11

K = 11 / (14×9) = 0.0873

Thus, <em>equilibrium constant is 0.0873</em>

3 0
3 years ago
What tests can be used to determine the composition of alum?
Natalka [10]
Other tests that could be performed to come to a verify your alum include a potassium flame test which would burn the potassium within the alum to be compared and/or a colorimetric <span>determination of alum test by observing the absorption rate of our alum. </span>
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