All categories

3 years ago

What is the mass (in grams) of 4.5 x 10^23 units of NaCl? could you also explain?

Chemistry

1 answer:

Vadim26 [7]3 years ago

4 0

Answer:

43.7 g

Explanation:

unit mass of NaCl = (23 + 35.5) u = 58.5 u

58.5 is the mass of one unit formula of NaCl (since NaCl is not a molecular compound)

1 u = 1.661×10^-24 g

if 1 unit formula of NaCl has 58.5 u, then 4.5×10²³ units of NaCl will have:

58.5 u × (1.661×10^-24 g/1 u) × 4.5×10²³ = 43.7 g

You might be interested in

In the laboratory a general chemistry student finds that when 2.84 g of KClO4(s) are dissolved in 107.70 g of water, the tempera

vredina [299]

Answer : The enthalpy change of dissolution of $KClO_4$ is 54.3 kJ/mole

Explanation :

Heat released by the reaction = Heat absorbed by the calorimeter + Heat absorbed by the water

$q=[q_1+q_2]$

$q=[c_1\times \Delta T+m_2\times c_2\times \Delta T]$

where,

q = heat released by the reaction

$q_1$ = heat absorbed by the calorimeter

$q_2$ = heat absorbed by the water

$c_1$ = specific heat of calorimeter = $1.55J/^oC$

$c_2$ = specific heat of water = $4.184J/g^oC$

$m_2$ = mass of water = 107.70 g

$\Delta T$ = change in temperature = $T_2-T_1=(22.80-20.34)=2.46^oC$

Now put all the given values in the above formula, we get:

$q=[(1.55J/^oC\times 2.46^oC)+(107.70g\times 4.184J/g^oC\times 2.46^oC)]$

$q=1112.3J=1.1123kJ$

Now we have to calculate the enthalpy change of dissolution of $KClO_4$

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = enthalpy change = ?

q = heat released = 1.1123 kJ

m = mass of $KClO_4$ = 2.84 g

Molar mass of $KClO_4$ = 138.55 g/mol

$\text{Moles of }KClO_4=\frac{\text{Mass of }KClO_4}{\text{Molar mass of }KClO_4}=\frac{2.84g}{138.55g/mole}=0.0205mole$

$\Delta H=\frac{1.1123kJ}{0.0205mole}=54.3kJ/mole$

Therefore, the enthalpy change of dissolution of $KClO_4$ is 54.3 kJ/mole

5 0

4 years ago

NaCl + H2O → NaOH + Cl2 + H2 Balance the equation. Choose "blank" if no coefficient is needed. NaCl + H2O → NaOH + Cl2 ++ H2

alexgriva [62]

The balanced equation is:

2NaCl + 2 H2o → 2 NaOH + Cl2 + H2

1- we put 2 NaCl to balance Cl2 on the other side.
2- we put 2 NaOH to balance Na
3- We put 2 H2O to balance H & O on the to sides

5 0

3 years ago

Read 2 more answers

What is the pH of a solution with a<br> POH of 8.35?

Paha777 [63]

Answer: The pH of the solution is 5.65

Explanation:

The relationship between the pH and the pOH is that $pH+pOH=14$ .

Given this, we can plug in the pOH and subtract that from 14.

$14-pOH=pH\\14-8.35=5.65$

I hope this helped! Pls give brainliest!! :)

3 0

2 years ago

What do scientists who study the human microbiome hope to achieve?

matrenka [14]

Answer:

Explanation:

Researchers hope to gain knowledge about how the microbiome contributes to health and disease states.

4 0

3 years ago

Read 2 more answers

If you have 485L of carbon dioxide combine with lithium hydroxide to produce lithium carbonate in water how many grams of lithiu

iVinArrow [24]

This method relies on the exothermic reaction of lithium hydroxide with carbon dioxide gas to create lithium carbonate (Li2CO3) solid and water (H2O).

might be wrong but....oh well

8 0

4 years ago