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sdas [7]
3 years ago
5

Point A(-4, -3) Point B (0, -6)

Mathematics
1 answer:
hram777 [196]3 years ago
8 0
Are you trying to find the slope between those points?
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<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Cint%20t%5E2%2B1%20%5C%20dt" id="TexFormula1" title="\frac{d}{dx} \
Kisachek [45]

Answer:

\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2}  t^2+1 \ \text{dt} \ = \ 2x^5-8x^2+2x-2

Step-by-step explanation:

\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2}  t^2+1 \ \text{dt} = \ ?

We can use Part I of the Fundamental Theorem of Calculus:

  • \displaystyle\frac{d}{dx} \int\limits^x_a \text{f(t) dt = f(x)}

Since we have two functions as the limits of integration, we can use one of the properties of integrals; the additivity rule.

The Additivity Rule for Integrals states that:

  • \displaystyle\int\limits^b_a \text{f(t) dt} + \int\limits^c_b \text{f(t) dt} = \int\limits^c_a \text{f(t) dt}

We can use this backward and break the integral into two parts. We can use any number for "b", but I will use 0 since it tends to make calculations simpler.

  • \displaystyle \frac{d}{dx} \int\limits^0_{2x} t^2+1 \text{ dt} \ + \ \frac{d}{dx} \int\limits^{x^2}_0 t^2+1 \text{ dt}

We want the variable to be the top limit of integration, so we can use the Order of Integration Rule to rewrite this.

The Order of Integration Rule states that:

  • \displaystyle\int\limits^b_a \text{f(t) dt}\  = -\int\limits^a_b \text{f(t) dt}

We can use this rule to our advantage by flipping the limits of integration on the first integral and adding a negative sign.

  • \displaystyle \frac{d}{dx} -\int\limits^{2x}_{0} t^2+1 \text{ dt} \ + \ \frac{d}{dx}  \int\limits^{x^2}_0 t^2+1 \text{ dt}  

Now we can take the derivative of the integrals by using the Fundamental Theorem of Calculus.

When taking the derivative of an integral, we can follow this notation:

  • \displaystyle \frac{d}{dx} \int\limits^u_a \text{f(t) dt} = \text{f(u)} \cdot \frac{d}{dx} [u]
  • where u represents any function other than a variable

For the first term, replace \text{t} with 2x, and apply the chain rule to the function. Do the same for the second term; replace

  • \displaystyle-[(2x)^2+1] \cdot (2) \ + \ [(x^2)^2 + 1] \cdot (2x)  

Simplify the expression by distributing 2 and 2x inside their respective parentheses.

  • [-(8x^2 +2)] + (2x^5 + 2x)
  • -8x^2 -2 + 2x^5 + 2x

Rearrange the terms to be in order from the highest degree to the lowest degree.

  • \displaystyle2x^5-8x^2+2x-2

This is the derivative of the given integral, and thus the solution to the problem.

6 0
3 years ago
Please help? , no decimals please,please explain to see picture. ​
dalvyx [7]

Answer:

8x\sqrt{3xy

Step-by-step explanation:

7 0
2 years ago
9 2/4 divide 1 1/3.
stepladder [879]

Answer:

7 1/8

Step-by-step explanation:

Convert the mixed fractions to normal fractions:

(9 * 4) + 2 = 38

(1 * 3) + 1 = 4

38/4 ÷ 4/3

Reduce it down as much as possible:

19/4 ÷ 4/3

Apply the fractions formula for division:

a / b ÷ c / d = a * d / b * c

19 * 3 / 2 * 4

57 / 8

Simplify:

7 1/8

5 0
3 years ago
Show how you got the answer
rewona [7]
Subtract the 45 minutes they were eating from 1:45pm since that’s when they arrived. You now have 1:00pm, you now just need to find out how long it is from 10:20 am to 1:00pm. HINT: it’s 2h 40m
5 0
3 years ago
1. The speed of light is approximately 3 x 108 m/s. How far does light travel in 5.0 x 10 seconds?
leonid [27]

Answer:

far

Step-by-step explanation:

jesus told me and u gotta trust jesus and not ur math teachers logic which is always weird

8 0
3 years ago
Read 2 more answers
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