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2 years ago

Find the solution of the system of equations.

Mathematics

1 answer:

liubo4ka [24]2 years ago

3 0

Answer:

The solution of the equation is (-1,-2)

Step-by-step explanation:

=> x - 6y = 11

-6x + 6y = -6

=> 6(x - 6y) = 6(11)

-6x + 6y = -6

=> 6x - 36y = 66

-6x + 6y = -6

=> -30y = 60

=> y = -2

=> x - 6(-2) = 11

=> x + 12 = 11

=> x = -1

Hence, the solution of the equation is (-1,-2)

Hoped this helped.

$BrainiacUser1357$

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3,047.092 in expanded form.

il63 [147K]

Answer:

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Step-by-step explanation:

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3 years ago

Question in picture A) 16/63 B)-16/63 C) 63/16 D) -63/16

Orlov [11]

ANSWER
$\tan(x + y) = - \frac{63}{16}$

EXPLANATION

We were given that,

$\csc(x) = \frac{5}{3}$

This implies that,

$\sin(x) = \frac{3}{5}$

We use the Pythagorean identity

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to get,

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We were also given that,

$\cos(y) = \frac{5}{13}$

This means that,

$\sin(y) = \sqrt{1 - {( \frac{5}{13}) }^{2} } = \frac{12}{13}$

This is because,

$0 < \: x \: < \frac{\pi}{2}$

$0 < \: y \: < \frac{\pi}{2}$

This angles are in the first quadrant so we pick the positive values.

$\tan(x + y) = \frac{ \sin(x + y) }{ \cos(x + y) }$

$\tan(x + y) = \frac{ \sin(x ) \cos(y) + \sin(y) \cos(x) }{ \cos(x) \cos(y) - \sin(x) \sin(y) }$

$\tan(x + y) = \frac{ \frac{3}{5} \times \frac{5}{13} + \frac{12}{13} \times \frac{4}{5} }{ \frac{4}{5} \times \frac{5}{13} - \frac{3}{5} \times \frac{12}{13} }$

$\tan(x + y) = - \frac{63}{16}$

The correct answer is D

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2 years ago

Fifty balls are numbered 1 to 50 and a red dot is painted on those balls that are a multiple of 6. The balls are mixed into a ba

djyliett [7]

Answer:

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Step-by-step explanation:

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