The equilibrium constant of the reaction is 0.0030.
The equation of the reaction is given as;
N2(g) + 3H2(g) ⇆ 2NH3 (g)
We have the following information at equilibrium;
[NH3] = 0.105 M
[N2] = 1.1 M
[H2] = 1.50 M
Hence, we can calculate the equilibrium constant using the relation;
K = [NH3]^2/ [N2] [H2]^3
Substituting values;
K = [0.105]^2/[ 1.1] [1.50]^3
K =0.011025 /3.7125
K= 0.0030
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<span>3x + 8x + 4x = 6x + 63
15x = 6x + 63
9x = 63
x = 7
so
5x+ 23 =5(7) + 23 = 35+23 = 58</span>
Y-1=4(x-(-2))
y-1=4x+8
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3(x+4) = 3(x) + 3(4) = 3x+12
3x+2x-4 = 5x-4