Answer:
58°
Step-by-step explanation:
A right triangle can be drawn to model the geometry of the problem. The hypotenuse of the triangle is the length of the string, 100 ft. The side opposite the angle is the height of the kite above the ground, 85 ft.
The mnemonic SOH CAH TOA reminds you of the relationship between sides and angles.
Sin = Opposite/Hypotenuse
sin(α) = (85 ft)/(100 ft) = 0.85
The angle whose sine is 0.85 is found using the arcsine (inverse sine) function:
α = arcsin(0.85) ≈ 58.2°
The angle of elevation is about 58°.
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When using your calculator to find the values of inverse trig functions, make sure it is in <em>degrees</em> mode. Otherwise, you're likely to get the answer in radians (≈ 1.01599 radians).
Answer:
0. | 2
Step-by-step explanation:
I took (0.2) and made an equal sign and gave me 0. | 2
Answer: 5/6
Step-by-step explanation: trust me on this
Use PEMDAS. So it would then simplify to [100+(586+4)]/5<19 then continueing that it would be [100+590]/5<19 and then 690/5<19 which finally will be 138<19 and that is a valid statement
Answer:

Step-by-step explanation:
Acceleration is second derivative of distance and are related as:

Integrating both sides w.r.to t

Using initial value

We have to calculate the distance covered in time interval [0,5], so:
![\int\limits^5_0 \frac{ds}{dt}=\int\limits^5_0 {\frac{1}{t+2}} \, dt\\\\s(t)=[ln|t+2|]^5_0\\\\s(t)=ln|5+2|+ln|0+2|\\\\s(t)=(ln|7|+ln|2|)\,ft](https://tex.z-dn.net/?f=%5Cint%5Climits%5E5_0%20%5Cfrac%7Bds%7D%7Bdt%7D%3D%5Cint%5Climits%5E5_0%20%7B%5Cfrac%7B1%7D%7Bt%2B2%7D%7D%20%5C%2C%20dt%5C%5C%5C%5Cs%28t%29%3D%5Bln%7Ct%2B2%7C%5D%5E5_0%5C%5C%5C%5Cs%28t%29%3Dln%7C5%2B2%7C%2Bln%7C0%2B2%7C%5C%5C%5C%5Cs%28t%29%3D%28ln%7C7%7C%2Bln%7C2%7C%29%5C%2Cft)