Answer:
the answer is number 4......
Answer:
x = 
Step-by-step explanation:
4x-y+2z = 8x+y-4
4x-8x-y+2z = 8x - 8x +y-4
-4x -y +2z= y-4
-4x -y+y +2z = y+y-4
-4x +2z = 2y-4
-4x+2z-2z = 2y-2z-4
-4x = 2y-2z-4
=
On an investment of $5000 with an interest payment of 5% = $250 at one year. At 3.5 years, the interest payments would total $250 × 3.5 = $875
Answer:
C(p) = 4,96 (in thousands of dollars)
l = 2980 $ invest in labor
k = 2980 $ invest in equipment
Step-by-step explanation:
Information we have:
Monthly output P = 450*l*k ⇒ k = P/450*l
But the production need to be 4000
Then k = 4000/450*l
Cost of production = l * k (in thousands of dollars)
C(l) = l + 4000/450*l
Taking derivatives (both members of the equation)
C´(l) = 1 - 400 /45*l² ⇒ C´(l) = 0 ⇒ 1 - 400/45l² = 0
45*l² - 400 = 0 ⇒ l² = 400/45
l = 2.98 (in thousands of dollars)
l = 2980 $ And
k = 400/45*l ⇒ k 400/45*2.98
k = 2.98 (in thousands of dollars)
C(p) = l + k
C(p) = 2980 + 2980
C(p) = 5960 $
