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Nataly_w [17]
2 years ago
10

A quadratic polynomial the sum of whose zeros is -3 and product is -10​

Mathematics
1 answer:
alukav5142 [94]2 years ago
6 0

Answer:

2 and -5 i think

Step-by-step explanation:

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1,023 + _____ = 1,400
denpristay [2]

Answer: 377

1,400 - 1,023 = 377

1,023 + 377 = 1,400

Step-by-step explanation: easy

5 0
2 years ago
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Tawnee is designing a playground in the shape of a rectangle. If Tawnee increases the length and width of the playground by a sc
svetlana [45]

Answer:

We conclude that If Tawnee increases the length and width of the playground by a scale factor of 2, the perimeter of the new playground will be twice the perimeter of the original playground.

Step-by-step explanation:

We know that the perimeter of a rectangle = 2(l+w)

i.e.

P = 2(l+w)

Here

  • 'l' is the length
  • 'w' is the width

Given that the length and width of the playground by a scale factor of 2

A scale factor of 2 means we need to multiply both length and width by 2.

i.e

P = 2× 2(l+w)

P' = 2 (2(l+w))

    = 2P      ∵ P = 2(l+w)

Therefore, we conclude that If Tawnee increases the length and width of the playground by a scale factor of 2, the perimeter of the new playground will be twice the perimeter of the original playground.

4 0
3 years ago
Read 2 more answers
Terms whose variables are the same are called what?
Ostrovityanka [42]
They are called like terms
8 0
3 years ago
How much sevens does it take to make 32?
Ksju [112]
Divide 7 by 32 and go from there
3 0
2 years ago
The bar graph shows the number of school days Jalen had homework and did not have homework during the first six months of
Oksanka [162]

Given:

<u>In July:</u>

Number of days he has done the homework = 6

Number of days he has not done the homework = 4

<u>In August:</u>

Number of days he has done the homework = 16

Number of days he has not done the homework = 7

<u>In September:</u>

Number of days he has done the homework = 14

Number of days he has not done the homework = 4

<u>In October:</u>

Number of days he has done the homework = 14

Number of days he has not done the homework = 8

<u>In November:</u>

Number of days he has done the homework = 16

Number of days he has not done the homework = 4

<u>In December:</u>

Number of days he has done the homework = 5

Number of days he has not done the homework = 10

To find the months in which the difference between the number of days with homework and with no homework greater than 6.

Now,

<u>In July,</u>

The difference between the number of days with homework and with no homework = 6-4 = 2

<u>In August,</u>

The difference between the number of days with homework and with no homework = 16-7 = 9

<u>In September,</u>

The difference between the number of days with homework and with no homework = 14-4 = 10

<u>In October,</u>

The difference between the number of days with homework and with no homework = 14-8 = 6

<u>In November,</u>

The difference between the number of days with homework and with no homework = 16-4 = 12

<u>In December,</u>

The difference between the number of days with homework and with no homework = 10-5 = 5

Hence,

In 3 months the difference between the number of days with homework and with no homework greater than 6 and these are: August, September, November.

4 0
3 years ago
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