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3 years ago

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An art museum had 275,760 visitors last year. The museum was open every day of the year except for 5 holidays. How many visitors

did the museum have each day, on average?

1 answer:

satela [25.4K]3 years ago

7 0

Answer:766 people on average because 275,760 divided 360 because 365=1 year 365-5=360 and 275760/360=766

Step-by-step explanation:

You might be interested in

The National Transportation Safety Board publishes statistics on the number of automobile crashes that people in various age gro

ra1l [238]

Answer:

a) Null hypothesis: $p\leq 0.12$

Alternative hypothesis: $p > 0.12$

b) $z_{\alpha}=1.64$

c) $z=\frac{0.134 -0.12}{\sqrt{\frac{0.12(1-0.12)}{1000}}}=1.362$

d) $p_v =P(z>1.362)=0.0866$

e) For this case since the statistic is lower than the critical value and the p value higher than the significance level we have enough evidence to FAIL to reject the null hypothesis so then we don't have information to conclude that the true proportion is higher than 0.12

Step-by-step explanation:

Information given

n=1000 represent the random sample selected

X=134 represent the number of young drivers ages 18 – 24 that had an accident

$\hat p=\frac{134}{1000}=0.134$ estimated proportion of young drivers ages 18 – 24 that had an accident

$p_o=0.12$ is the value that we want to verify

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic

$p_v{/tex} represent the p valuePart aWe want to verify if the population proportion of young drivers, ages 18 – 24, having accidents is greater than 12%: Null hypothesis:[tex]p\leq 0.12$

Alternative hypothesis: $p > 0.12$

The statistic would be given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Part b

For this case since we are conducting a right tailed test we need to find a critical value in the normal standard distribution who accumulates 0.05 of the area in the right and we got:

$z_{\alpha}=1.64$

Part c

For this case the statistic would be given by:

$z=\frac{0.134 -0.12}{\sqrt{\frac{0.12(1-0.12)}{1000}}}=1.362$

Part d

The p value can be calculated with the following probability:

$p_v =P(z>1.362)=0.0866$

Part e

For this case since the statistic is lower than the critical value and the p value higher than the significance level we have enough evidence to FAIL to reject the null hypothesis so then we don't have information to conclude that the true proportion is higher than 0.12

8 0

2 years ago

How do I solve this? Step by step

shutvik [7]

Answer:

24.

Step-by-step explanation:

Substitute each instance of x with a 3.

That leaves us with 3^2 + 3x - 5 + 3^2 - 3x + 11.

Combine like terms.

2(3^2) + 6.

Simplify.

2(9) + 6

18 + 6

24.

8 0

3 years ago

Read 2 more answers

Consider the equations and graph below.

Len [333]

Answer:help pls

Step-by-step explanation:

8 0

2 years ago

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What is the sign of 3x y3xy3, x, y when x>0x>0x, is greater than, 0 and y<0y<0y, is less than, 0?

jekas [21]

Answer:

$Negative$

Step-by-step explanation:

$We\ have\ to\ find\ sign\ of\ 3xy^3\\\\x>0\ and\ y0,y$

4 0

3 years ago

Read 2 more answers

Tammy conducted a survey to find the favorite subject of the students at her school. She asked 25 students from her math class w

almond37 [142]

Tammy's sample may not be considered valid because, on the first hand, it is said that she only asked students from her " Math Class".
If she wants to have a survey to find out the favorite subject of the students at her school, she must conduct a survey involving all the students in her school, not just in her class. What she did is just subjective. She should use a tally listing the different subjects and compare the number of students per subject. This way, she can have an objective representation of the least liked subjects and the most liked subjects of the students on her school.
Illustrating her survey through statistics may be more reliable and valid because it shows frequencies in which she can calculate easily and accurately the percentage of the number of students per subject, in a more objective manner.

7 0

3 years ago