The correct question is: evaluate
![\sqrt[3]{- \frac{8}{125} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B-%20%5Cfrac%7B8%7D%7B125%7D%20%7D%20)
The
answer is: option B. -2 / 5Explanation:![\sqrt[3]{- \frac{8}{125} }=- \frac{ \sqrt[3]{8} }{ \sqrt[3]{125} } =- \frac{ \sqrt[3]{2^3} }{ \sqrt[3]{5^3} } =- \frac{2}{5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-%20%5Cfrac%7B8%7D%7B125%7D%20%7D%3D-%20%5Cfrac%7B%20%5Csqrt%5B3%5D%7B8%7D%20%7D%7B%20%5Csqrt%5B3%5D%7B125%7D%20%7D%20%3D-%20%5Cfrac%7B%20%5Csqrt%5B3%5D%7B2%5E3%7D%20%7D%7B%20%5Csqrt%5B3%5D%7B5%5E3%7D%20%7D%20%3D-%20%5Cfrac%7B2%7D%7B5%7D%20)
Answer:
3 * 10^6 if the answer is 3.64 * 10^6, you really ought to argue the meaning of estimate with your instructor.
Step-by-step explanation:
This is a very valuable question. Put your calculator away when you answer it. Using a calculator is sort of cheating.
1.3 * 10^3 roughly is roughly 1 * 10^3
2.8*10^3 hours is roughly 3 * 10^3
Forget the powers for now and just work with the 1 and 3
1*3 equals 3.
10^3 * 10^3 = 10^6 when the base of two numbers is the same (10 in this case) then the powers are added.
10^(3 + 3) = 10^6
So the answer is roughly 3*10^6
Now you can take out your calculator and get the answer.
1.3*10^3 * 2.8 * 10^3 = 3.64 * 10 ^ 6
Notice that the estimate (done in my head) is close enough to tell you what the answer should be. On a test, that's a very handy skill.
The value k = 5 will shift the parent function 5 units up. i.e. vertical shift of 5 units up.
A. cardinality means no of elements present in the set.
b. no of proper set = 2^n - 1
c. no of subset = n
2^n = 512
2^n = 2^9
n = 9.
Q. power set:
a. { 3,7,9} = {3,7,9,(3 7),(7 9),(9 3)}
Answer:
Exact Form:
Y= 43/9
Decimal Form:
Y= 4.7
Mixed Number Form:
4 7/9
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.
