Answer:
35+15=50 or 35$+15$=50$
Step-by-step explanation:
If its for twelve months
35$+180$=215$
Answer: X=4 and y=4
Step-by-step explanation:
Answer:
[0,1] and [-1,0]
Step-by-step explanation:
We have the function
to determine consecutive values of x between which each real zero is located we have to replace the function with different values and then analyze the results.
We are going to replace the function with x=0,
![f(0)=-14.(0)^4-7.(0)^3-18.(0)^2+17.(0)+11\\f(0)=11](https://tex.z-dn.net/?f=f%280%29%3D-14.%280%29%5E4-7.%280%29%5E3-18.%280%29%5E2%2B17.%280%29%2B11%5C%5Cf%280%29%3D11)
Now we are going to replace with x=1,
![f(1)=-14.(1)^4-7.(1)^3-18.(1)^2+17.(1)+11\\f(1)=-14-7-18+17+11\\f(1)=-11](https://tex.z-dn.net/?f=f%281%29%3D-14.%281%29%5E4-7.%281%29%5E3-18.%281%29%5E2%2B17.%281%29%2B11%5C%5Cf%281%29%3D-14-7-18%2B17%2B11%5C%5Cf%281%29%3D-11)
With x=2,
![f(2)=-14.(2)^4-7.(2)^3-18.(2)^2+17.(2)+11\\f(2)=-224-56-72+34+11\\f(2)=-307](https://tex.z-dn.net/?f=f%282%29%3D-14.%282%29%5E4-7.%282%29%5E3-18.%282%29%5E2%2B17.%282%29%2B11%5C%5Cf%282%29%3D-224-56-72%2B34%2B11%5C%5Cf%282%29%3D-307)
Now with x=-1,
![f(-1)=-14.(-1)^4-7.(-1)^3-18.(-1)^2+17.(-1)+11\\f(-1)=-14+7-18-17+11\\f(-1)=-31](https://tex.z-dn.net/?f=f%28-1%29%3D-14.%28-1%29%5E4-7.%28-1%29%5E3-18.%28-1%29%5E2%2B17.%28-1%29%2B11%5C%5Cf%28-1%29%3D-14%2B7-18-17%2B11%5C%5Cf%28-1%29%3D-31)
With x=-2,
![f(-2)=-14.(-2)^4-7.(-2)^3-18.(-2)^2+17.(-2)+11\\f(-2)=-224+56-72-34+11\\f(-2)=-195](https://tex.z-dn.net/?f=f%28-2%29%3D-14.%28-2%29%5E4-7.%28-2%29%5E3-18.%28-2%29%5E2%2B17.%28-2%29%2B11%5C%5Cf%28-2%29%3D-224%2B56-72-34%2B11%5C%5Cf%28-2%29%3D-195)
We have to analyze:
We have that f(2) and f(1) have the same signs both are negatives this means that there isn't a zero between the interval [1,2].
We have that f(1) and f(0) have opposite signs this means that there is a zero between the interval [0,1].
f(0) and f(-1) have opposite signs too, then there's also a zero in the interval [-1,0].
And finally, f(-1) and f(-2) have the same signs then there isn't a zero in the interval [-2,-1]
The graph of the function shows that the answer is correct: