Is this correct if you answer I’ll give brainlest

Mathematics

2 answers:

Illusion [34]3 years ago

4 0

Answer:

verticle

you are correct

Step-by-step explanation:

Lemur [1.5K]3 years ago

4 0

Answer:

the answer is currently incorrect x is horizontal

Step-by-step explanation:

trust me I gurante this

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On average, Tanner has noticed that 22 trains pass by his house daily (24 hours) on the nearby train tracks. What is the probabi

blondinia [14]

Answer:

0.11069

Step-by-step explanation:

We will assume that the trains pass by his house following a uniform distribution with values between 0 and 24. The probability of a train passing on a 9-hour time period is 9/24 = 3/8 = 0.375. Lets call Y the amount of trains passing by his house during that 9-hour period. Y follows a Binomail distribution with parameters 22 and 0.375.

P(Y ≤ 5) = P(Y = 0) + P(Y=1) + P(Y=2) + P(Y=3) + P(Y=4) + P(Y=5) =

${22 \choose 0} * 0.375^0*(1-0.375)^{22} + {22 \choose 1}*0.375^1*(1-0.375)^{21} +\\\\{22 \choose 2} * 0.375^2*(1-0.375)^{20} + {22 \choose 3}*0.375^3*(1-0.375)^{19} + \\{22 \choose 4} * 0.375^4*(1-0.375)^{18} + {22 \choose 5}*0.375^5*(1-0.375)^{17} = 0.11069$

I hope that works for you!

4 0

3 years ago

What is the sum and product to this quadratic equation.<br> x^2+7x+2=0

Pani-rosa [81]

I don't know specifically what the sum and product of an equation is but

factor using quadratic formula

if you have an equation in ax^2+bx+c=0 then you can solve for x using

$x= \frac{-b+ \sqrt{b^2-4ac} }{2a}$ or $x= \frac{-b- \sqrt{b^2-4ac} }{2a}$

so input
a=1
b=7
c=2

$x= \frac{-7+ \sqrt{7^2-4(1)(2)} }{2(1)}$
$x= \frac{-7+ \sqrt{49-8} }{2}$
$x= \frac{-7+ \sqrt{41} }{2}$ =aprox -0.2984378812836

$x= \frac{-7- \sqrt{7^2-4(1)(2)} }{2(1)}$
$x= \frac{-7- \sqrt{49-8} }{2}$
$x= \frac{-7 \sqrt{41} }{2}$ =aprox -6.7015621187165

4 0

3 years ago

A recipe of salad dressing calls for ¼ cup vinegar to ⅔ cup oil. How many cups of oil are needed for each cup of vinegar?

Akimi4 [234]

Answer:

$2\frac{2}{3} \ cups$ of oil are needed for each cup of vinegar.