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Gre4nikov [31]
3 years ago
6

Write the equation of a line that has a slope of -4 and goes through (-2,7).

Mathematics
1 answer:
Anni [7]3 years ago
7 0

Answer:

y = -4x - 1

Step-by-step explanation:

Equation of a line is given as:

y = mx + b

Where

m is the slope

and

b is the y-intercept (y-axis cutting point)

Since we know slope is -4, we can write:

y= mx + b

y = -4x+ b

Given the point (-2,7) , we can say:

x = -2

and

y = 7

Plugging these 2 values, we can solve for b:

y = -4x + b

7 = -4(-2) + b

7 = 8 + b

b = 7 - 8

b = -1

Now, we have the equation:

y = -4x - 1

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olganol [36]

Answer:

H.''n is not divisible by 6 and n is not divisible by both 2 and 3.

Step-by-step explanation:

We are given that  a statement ''n is divisible by 6 or n is divisible by both 2 and 3.''

We have to write the negation of the  given statement.

Negation: If  a statement p is true then its negations is  p is false.

n is divisible by 6 then negation is n is not divisible by 6.

n is divided by both 2 and 3 then negation is n is not divisible  by both 2 and 3.

Therefore, negation of given statement

''n is not divisible by 6 and n is not divisible by both 2 and 3.

Hence, option H is true.

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a lady walks into a store and steals a $100 bill from the register without the owner's knowledge.she comes back 5 minutes later
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2. The Welcher Adult Intelligence Test Scale is composed of a number of subtests. On one subtest, the raw scores have a mean of
IgorC [24]

Answer:

a) 37.31 b) 42.70 c) 0.57 d) 0.09

Step-by-step explaanation:

We are regarding a normal distribution with a mean of 35 and a standard deviation of 6, i.e., \mu = 35 and \sigma = 6. We know that the probability density function for a normal distribution with a mean of \mu and a standard deviation of \sigma is given by

f(x) = \frac{1}{\sqrt{2\pi}\sigma}\exp[-\frac{(x-\mu)^{2}}{2\sigma^{2}}]

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f(x) = \frac{1}{\sqrt{2\pi}6}\exp[-\frac{(x-35)^{2}}{2(6^{2})}]

Let X be the random variable that represents a row score, we find the values we are seeking in the following way

a)  we are looking for a number x_{0} such that

P(X\leq x_{0}) = \int\limits^{x_{0}}_{-\infty} {f(x)} \, dx = 0.65, this number is x_{0}=37.31

you can find this answer using the R statistical programming languange and the instruction qnorm(0.65, mean = 35, sd = 6)

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P(X\leq x_{1}) = \int\limits^{x_{1}}_{-\infty} {f(x)} \, dx = 0.9, this number is x_{1}=42.70

you can find this answer using the R statistical programming languange and the instruction qnorm(0.9, mean = 35, sd = 6)

c) we find this probability as

P(28\leq X\leq 38)=\int\limits^{38}_{28} {f(x)} \, dx = 0.57

you can find this answer using the R statistical programming languange and the instruction pnorm(38, mean = 35, sd = 6) -pnorm(28, mean = 35, sd = 6)

d) we find this probability as

P(41\leq X\leq 44)=\int\limits^{44}_{41} {f(x)} \, dx = 0.09

you can find this answer using the R statistical programming languange and the instruction pnorm(44, mean = 35, sd = 6) -pnorm(41, mean = 35, sd = 6)

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