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babymother [125]
1 year ago
14

-19>g-24

e=" - 19 \ \textgreater \ g - 24" alt=" - 19 \ \textgreater \ g - 24" align="absmiddle" class="latex-formula">whats the answer
Mathematics
1 answer:
KatRina [158]1 year ago
6 0
\begin{gathered} -19>g-24 \\ -19+24>g \\ 5>g \end{gathered}

start by adding 24 on both sides and simplify

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Which represents the solution of the graphed system of equations, y=x^2-2x and y=-2x-1
elena55 [62]

Answer:

x = √(-1) = i

Since the value of √(-1) is not real.

The system has no real solution.

Step-by-step explanation:

The solution to the system of equations is at the point where they intercept each other.

y1 = y2

For the given equation;

y=x^2-2x and y=-2x-1

To get the where they intercept, we will equal both equations;

y=x^2-2x = -2x-1

x^2 - 2x = -2x - 1

x^2 - 2x + 2x + 1 =0

x^2 +1 = 0

x^2 = -1

x = √(-1) = i

Since the value of √(-1) is not real.

The system has no real solution.

6 0
3 years ago
Michelle will be 72 years old in eighteen years. How old is Michelle now? A. 90 years old B. 54 years old C. 36 years old D. 49
Katen [24]
Subtract 18 from 72 to get Michelle's current age.

72 - 18 = 54
5 0
3 years ago
Read 2 more answers
Help don't forget to put the work thank you
marysya [2.9K]

Answer:

<em>(J) </em>

Step-by-step explanation:

If the scale factor of dilation is greater than 1, the image is an enlargement.

If the scale factor of dilation is between 0 and 1, the image is a reduction.

6 0
3 years ago
Ronald States that the number 1/11 is not rational because,when converted into a decimal,it does not terminate.nathaniel says it
svet-max [94.6K]
Nathaniel is correct mkayy
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3 years ago
How do i turn reapeating decimals into fractions?
inysia [295]
Easy example that shows 0.999\ldots=1:

Let x=0.999\ldots=0.\overline9.

Then 10x=9.999\ldots=9.\overline9.

So 10x-x=9.\overline9-0.\overline9, or 9x=9, and so x=1.

The basic idea is to find the period of the repeating decimal, move the n digits belonging to one period over to the left of the decimal point by multiplying by 10^n, then subtract the original repeating decimal from this new number, and finally divide by 10^n-1.

A slightly more complicated example:

Let x=0.142857142857142857\ldots=0.\overline{142857}.

Then 10^6x=142857.\overline{142857}.

Then 10^6x-x=142857.\overline{142857}-0.\overline{142857}, or

999999x=142857\implies x=\dfrac{142857}{999999}=\dfrac17
6 0
2 years ago
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