I think the answer you are looking for is $2,592
Answer:
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try mo magsagot
To get the extrema, derive the function.
You get y' = 2x^-1/3 - 2.
Set this equal to zero, and you get x=0 as the location of a critical point.
Since you are on a closed interval [-1, 1], those points can also have an extrema.
Your min is right, but the max isn't at (1,1). At x=-1, you get y=5 (y = 3(-1)^2/3 -2(-1); (-1)^2/3 = 1, not -1).
Thus, the maximum is at (-1, 5).
Answer:
Step-by-step explanation:
-8x^2 - 12 + 7x^2 - 9x + 3
-x^2 - 9x - 9
Ok, sin = prep / hyp
so, perpendicular = 1 , and hypo = 4
so, base = sq. root ( 16-1 ) = root 15
and tan = prep / base = 1 / root (15)
