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IgorC [24]
2 years ago
13

Need help with school

Mathematics
2 answers:
Scrat [10]2 years ago
6 0
The answer would be x=7.2m
Scorpion4ik [409]2 years ago
5 0

Answer:

x = 7.2m

Step-by-step explanation:

Because it is a right triangle, you can use the Pythagorean theorem:

4^2+6^2 = x^2

16+36 = x^2

52 = x^2

sqrt52 = x

7.2 = x

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A factory that manufactures bolts is performing a quality control experiment. Each object should have a length of no more than c
disa [49]

Answer:

There is sufficient evidence. A further explanation is provided below.

Step-by-step explanation:

According to the question,

The alternative as well as null hypothesis will be:

H_0:\mu = 16

H_a:\mu>16

The test statistics will be:

⇒ z = \frac{\frac{\bar x - \mu}{\sigma} }{\sqrt{n} }

By putting the values, we get

⇒    =\frac{\frac{16.06-16}{0.24} }{\sqrt{96} }

⇒    =\frac{\frac{0.06}{0.24} }{\sqrt{96} }

⇒    =2.45

Or,

The p-value will be:

= 0.0071

i.e.,

⇒ p-value< \alpha

Thus the above is the correct answer.

6 0
3 years ago
Which property of equality could be used to solve x - (-6) = 18?
oksian1 [2.3K]

Answer:subtraction property

Step-by-step explanation:

Two a negative and a negative makes a positive so it would be x+6=18 so u do the opposite on both sides so it would be subtraction

8 0
3 years ago
uppose we want to build a rectangular storage container with open top whose volume is $$ cubic meters. Assume that the cost of m
Ainat [17]

Answer:

a = length of the base = 2.172 m

b = width of the base = 1.357 m

c = height = 4.072 m

Step-by-step explanation:

Suppose we want to build a rectangular storage container with open top whose volume is 12 cubic meters. Assume that the cost of materials for the base is 12 dollars per square meter, and the cost of materials for the sides is 8 dollars per square meter. The height of the box is three times the width of the base. What’s the least amount of money we can spend to build such a container?

lets call a = length of the base

b = width of the base

c = height

V = a.b.c = 12

Area without the top:

Area = ab + 2bc + 2ac

Cost  = 12ab + 8.2bc + 8.2ac

Cost = 12ab + 16bc + 16ac

height = 3.width

c = 3b

Cost = 12ab + 16b.3b + 16a.3b = 12ab + 48b² + 48ab = 48b² + 60ab

abc = 12 → ab.3b = 12 → 3ab² = 12 → ab² = 4 → a = 4/b²

Cost = 48b² + 60ab = 48b² + 60b.4/b² = 48b² + 240/b

C(b) = 48b² + 240/b

C'(b) = 96b - 240/b²

Minimum cost: C'(b) = 0

96b - 240/b² = 0

(96b³ - 240)/b² = 0

96b³ - 240 = 0

96b³ = 240

b³ = 240/96

b³ = 2.5

b = 1.357m

c = 3b = 3*1.357 = 4.072m

a = 4/b² = 2.172m

6 0
3 years ago
Please help fill it in I’ll mark you as brainlist
neonofarm [45]

Answer:

it so blurry

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Assume a fair deck of playing cards. Find the probability of drawing a 10, replacing it and drawing an ace.
cupoosta [38]

Answer:

There are 52 cards in a deck. The total number of outcomes possible when picking 2 cards and replacing them is 52 * 52 = 2704.

There are 4 10s and 4 aces so the total number of successful outcomes = 4 * 4 = 16.

Probability = 16 / 2704 = 1 / 169

6 0
2 years ago
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