Answer:
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Step-by-step explanation:
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<span>Form a sequence that has two arithmetic means between -13 and 89. a. -13, 33, 43, 89 c. -13, 21, 55, 89 b. -18, -36, -72, -144 d. -18, -81, -144
Solution:
Since it has to be between -13 and 89, letter d and b are not anymore considered to be the answer.
for a:
33-(-13)=46=d
43-33=10=d the value for this d is different from the two sequence,
89-43=46=d
they have different value for d, thus this is not the answer!
for c:
21-(-13)=34=d
55-21=34=d
89-55=34=d
they have the same value for d, thus the correct answer is </span><span> c. -13, 21, 55, 89</span>
Answer:
Domain: (-∞,∞), Range: [2,∞)
Answer:
.
Step-by-step explanation:
For part A, you simply add the two functions a(x) and b(x). The resulting function is then (a+b)(x) = 5x +2.
For part B, you multiply the functions a(x) and b(x). Using the FOIL method, we obtain, 6x^2 -24x + 20x - 80. Simplifying, we get, (a*b)(x) = 6x^2 -4x - 80.
For part C, you replace x in the function a(x) with the expression from b(x). This results to: a[b(x)] = 3(2x - 8) +10. Simplifying, a[b(x)] = 6x - 14.
