Pls answer this question

Help me please .......

kati45 [8]

Answer:

$\huge\boxed{\sf No}$

Step-by-step explanation:

The ordered pairs for the given relation are:

=> {(6,2)(-1,2)(-1,-1)(4,3)}

Domain => x-inputs of the ordered pairs

Domain => (6,-1,4)

Range => y-inputs of the ordered pairs

Range = (2,-1,3)

Since, the values in the domain (-1) are being repeated, this relation is not a function.

Hope this helped!

~AnonymousHelper1807

6 0

3 years ago

Solve: 3(2d-1) - 2d=4(d-2)+5

nadezda [96]

3(2D-1)-2D = 4(D-2)+5
6D-3-2D = 4D-8+5
4D-3 = 4D-8+5
4D-3 = 4D-3
4D = 4D-6
0 = -6
The answer is C, no solution

3 0

3 years ago

What percentage of the semi circle is shaded?

mezya [45]

The percentage of the semicircle shaded section is approximately 23,606 %.

The percentage of the area of the semicircle is equal to the ratio of the semicircle area minus the half-cross area to the semicircle area. In other words, we have the following expression:

$r = \left(\frac{A_{s}-A_{h}}{A_{s}} \right)\times 100\,\%$

$r = \left(1-\frac{A_{h}}{A_{s}} \right)\times 100\,\%$ (1)

Where:

$A_{h}$ - Area of the half cross, in square centimeters.
$A_{s}$ - Area of the semicircle, in square centimeters.
$r$ - Percentage of the shaded section of the semicircle.

And the percentage of the shaded section is:

$r = \left[1-\frac{4 \cdot (2\,cm)^{2}+4\cdot \left(\frac{1}{2} \right)\cdot (2\,cm)^{2}}{0.5\cdot \pi\cdot (16\,cm^{2}+4\,cm^{2})} \right]\times 100$

$r \approx 23.606\,\%$

The percentage of the semicircle shaded section is approximately 23,606 %.

We kindly invite to check this question on percentages: brainly.com/question/15469506

3 0

2 years ago

Among all rectangles that have a perimeter of 182, find the dimensions of the one whose area is largest.

Evgen [1.6K]

Answer:

The largest rectangle of perimeter 182 is a square of side 45.5

Step-by-step explanation:

Maximization Using Derivatives

The procedure consists in finding an appropriate function that depends on only one variable. Then, the first derivative of the function will be found, equated to 0 and find the maximum or minimum values.

Suppose we have a rectangle of dimensions x and y. The area of that rectangle is:

$A=x.y$

And the perimeter is

$P=2x+2y$

We know the perimeter is 182, thus

$2x+2y=182$

Simplifying

$x+y=91$

Solving for y

$y=91-x$

The area is

$A=x.(91-x)=91x-x^2$

Taking the derivative:

$A'=91-2x$

Equating to 0

$91-2x=0$

Solving

$x=91/2=45.5$

Finding y

$y=91-x=45.5$

The largest rectangle of perimeter 182 is a square of side 45.5

6 0

3 years ago

1.Each side of a square has a length of 5x. Use your area expression to find the area of the square when x = 2.2 centimeters. Sh

NARA [144]

1. The area is l * w, so just multiply 5x by 5x. Replacing x with 2.2 gets:
(5 * 2.2) * (5 * 2.2)

11 * 11
= 121

So, the area of the square when x = 2.2 centimeters is 121 sq cm.

2. The expression for this equation would be:
6(y + 4)

And using the distributive property on this to get the simplified expression, just multiply both y and 4 by 6.

6 * y + 6 * 4
6y + 24
So, your expression is 6y + 24.

3. For this one, let's make y's value 3.5 instead of 3 1/2 to make it easier to solve.

We just use the above expression to solve.
6 * 3.5 + 6 * 4
21 + 24
= 45

So, the area of the rectangle when y = 3 1/2 is 45 sq in.

4. For this last one, let's use the formula w = A/l to form an expression that will represent the width.

w = 8w + 18/2

Now, let's simplify it by dividing 8w and 18 by 2.
w = 8w/2 + 18/2

w = 4w + 9

So the expression to represent the width of the rectangle is 4w + 9.
Hope this helped!

4 0

3 years ago