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coldgirl [10]
2 years ago
7

A student selecting 3 classes for Winter quarter there are 4 drawing and design courses 3 general education courses and 3 other

majors that can fit in their schedule it said student is only taking one course from each category determine the number of possible class schedules
Mathematics
1 answer:
pychu [463]2 years ago
5 0

Answer:

36 possible class schedules

Step-by-step explanation:

1st - 4 ways

2nd - 3 ways

3rd - 3 ways

4 x 3 x 3 = 36 possible class schedules

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Dustin and Janelle sold packs of trading cards to earn extra money before summer break. They sold each box for $51 which include
Grace [21]

Answer:

Dustin sold 28 packs

Step-by-step explanation:

3 0
2 years ago
The most recent census for a city indicated that there were 919,716 residents. The population of the city is expected to increas
OLEGan [10]

Answer:

1,474,951.

Step-by-step explanation:

Given a population that increases by a constant percentage, we can model the population's growth using the exponential model.

P(t)=P_o(1+r)^t,$ where \left\{\begin{array}{lll}P_o=$Initial Population\\r$=Growth rate\\$t=time (in years)\end{array}\right\\P_o=919,716\\r=3.7\%=0.037\\$t=13 years

Therefore, the population of the city in 13 years time will be:

P(t)=919,716(1+0.037)^{13}\\\\=919,716(1.037)^{13}\\\\=1,474,950.9\\\\\approx 1,474,951

The population be at that time will be approximately 1,474,951.

3 0
3 years ago
According to the 2000 Census the population of Canton was 7,720. Holly Spring's population was 3,200. Canton's population increa
Kazeer [188]
Firstly, the rate of increase of Canton = 80/7720 = 0.010
The rate of increase of HP = 120/3200 = 0.0375
Apply  the formula of compound interest==> A =A'(1+i)^n
The population will be equal when the following equality is satisfied

7720(1+0.01)^n = 3200(1+0.0375)^n

or

7720x1.01^n = 3200x1.0375^n

Divide both sides by 3200 ===>(193/80)x1.01^n=1.0375^n
8 0
3 years ago
Read 2 more answers
Somebody help me with this
zubka84 [21]

Answer:

1

Step-by-step explanation:

when multiplying fractions it doesn’t matter if they have the same denominator (bottom) just multiply straight across

(6/12)x(6/3)

36/36

1

4 0
2 years ago
RS bisects TU at Q. If TQ=5k-9 and QU=15-x
snow_lady [41]

Answer:

x = 4, TU = 22

Step-by-step explanation:

Given that TS bisects TU at Q , then

TQ = QU , substitute values

5x - 9 = 15 - x ( add x to both sides )

6x - 9 = 15 ( add 9 to both sides )

6x = 24 ( divide both sides by 6 )

x = 4

Thus

TU = 5x - 9 + 15 - x = 4x + 6 = 4(4) + 6 = 16 + 6 = 22

4 0
3 years ago
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