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3 years ago

Which inequality is true?

Mathematics

2 answers:

LenaWriter [7]3 years ago

4 0

Answer:

its B the answer is b

Step-by-step explanation:

Ksivusya [100]3 years ago

4 0

the answer is D because i am bigger brain than you

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Noah's town voted on a new speed limit. 50% of the 58 votes were in favor of the new speed limit. How many votes were in favor?

True [87]

This problem is asking us to find 50% of 58.

Answer is provided in the image attached.

29 Votes

4 0

4 years ago

Read 2 more answers

-1/3x-4/3y=-2 1/3x-2/3y=4 using elimination

Minchanka [31]

-1/3x-4/3y=2

1/3x-2/3y=4

First realize that the coefficient of x is -1/3 and 1/3 which can be eliminated with addition

Adding the two equations together gets

-6/3y=6

Simplify

-2y=6

y=-3

Substitute back into original equation

1/3x-2/3(-3)=4

1/3x+2=4

1/3x=2

x=6

Answer

x=6, y=-3

Check answer

-1/3(6)-4/3(-3) =?= 2

-2+4=2

2=2

Done!

5 0

2 years ago

Solve a-d please i really dont understand

valkas [14]

So i think what you do is if you make a number line like this:

1...2...3...4...5...6...7...8

you have to find out how many numbers are in between 4 and 7, so I would be 3 because there are 3 numbers I between 4-7.

so

a) 3
b) 6
c) 14
d) 8

5 0

4 years ago

For an arithmetic sequence, a35=57. If the common difference is 5. Find a1 and the sum of the first 61 terms.

Flauer [41]

$\displaystyle\bf\\a_{35}=57\\r=5\\----\\a_1=?\\S_{61}=?\\----\\Solve:\\1)\\a_1=a_{35}-(35-1)\times r=57-34\times 5=57-170=-113\\\boxed{\bf a_1=-113}\\\\$

$\displaystyle\bf\\2)\\A_{61}=a_1+(61-1)\times r=-113+60\times5=-113+300=187\\\\S_{61}=(-113)+(-108)+(-103)+...+(-8)+(-3)+2+7+12+...+187\\\\S_{61}=SA+SB\\\\SA=(-113)+(-108)+(-103)+...+(-8)+(-3)=-(3+8+103+108+113)\\\\n=\frac{113-8}{5}+1=\frac{105}{5}+1=21+1=22~terms\\SA=-\Big( \frac{n(113+3)}{2} \Big)=-\Big( \frac{22\times116}{2} \Big)=-11\times116 =-1276$

$\displaystyle\bf\\SB=2+7+12+...+187\\\\n=\frac{187-2}{5}+1=\frac{185}{5}+1=37+1=38~terms\\\\SB=\frac{n(187+2)}{2}=\frac{38\times189}{2}=19\times189=3591\\\\S_{61}=SA+SB=-1276+3591=2315\\\\\boxed{\bf S_{61}=2315}$