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stich3 [128]
3 years ago
10

HELP HELP PLEASEEEEE CORRECTLYYYYT

Mathematics
1 answer:
Kaylis [27]3 years ago
4 0

Answer:

84 degree

Step-by-step explanation:

the new supposed line is parallel to the given parallel lines..

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A cup slides off a 2.5 m high table with a speed of 2.8 m/s to the right. We can ignore air resistance. What was the cup's horiz
azamat

Answer:

Horizontal distance = 1.98 m (Approx)

Step-by-step explanation:

Given:

Height = 2.5 m

Speed v = 2.8 m/s

Find:

Horizontal displacement

Computation:

s = ut + (1/2)gt²

2.5 = (1/2)(9.8)t²

t² = 0.5102

t = 0.7079 s

Horizontal distance = (v)(t)

Horizontal distance = (2.8)(0.7079)

Horizontal distance = 1.98 m (Approx)

5 0
3 years ago
What is the approximate distance between the points (-3, -4) and (-8, 1) on a coordinate grid
tatyana61 [14]
\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~ -3 &,& -4~) 
%  (c,d)
&&(~ -8 &,& 1~)
\end{array}\\\\\\ %  distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
d=\sqrt{[-8-(-3)]^2+[1-(-4)]^2}\implies d=\sqrt{(-8+3)^2+(1+4)^2}
\\\\\\
d=\sqrt{25+25}\implies d=\sqrt{2\cdot 25}\implies d=\sqrt{2\cdot 5^2}\implies d=5\sqrt{2}
4 0
3 years ago
Read 2 more answers
What is the radius of the circle given the equation x2 - 6x + y2 + 10y + 18 = 0?
arlik [135]
The\ equation\ of\ a\ circle:(x-a)^2+(y-b)^2=r^2\\\\(a;\ b)-a\ coordinates\ of\ the\ center\\r-a\ radius

x^2-6x+y^2+10y+18=0\\\\x^2-2x\cdot3+y^2+2y\cdot5=-18\\\\x^2-2x\cdot3+3^2+y^2+2y\cdot5+5^2=-18+3^2+5^2\ \ \ |use\ (a\pm b)^2=a^2\pm2ab+b^2\\\\(x-3)^2+(y+5)^2=-18+9+25\\\\(x-3)^2+(y+5)^2=16\\\\therefore\\\\Answer:\boxed{r=\sqrt{16}=4}
7 0
3 years ago
Find the equation of the line passing through the point (8, -4) and slope -4.
ehidna [41]

Answer:

y+4x=36

Step-by-step explanation:

the answer isn't in the choice

3 0
3 years ago
Over which interval is the graph of f(x) = –x2 + 3x + 8 increasing?
vivado [14]
Hello there!

To find the increasing intervals for this graph just based on the equation, we should find the turning points first.

Take the derivative of f(x)...
f(x)=-x²+3x+8
f'(x)=-2x+3

Set f'(x) equal to 0...
0=-2x+3
-3=-2x
3/2=x

This means that the x-value of our turning point is 3/2. Now we need to analyze the equation to figure out the end behavior of this graph as x approaches infinity and negative infinity.
Since the leading coefficient is -1, as x approaches ∞, f(x) approaches -∞ Because the exponent of the leading term is even, the end behavior of f(x) as x approaches -∞ is also -∞.

This means that the interval by which this parabola is increasing is...
(-∞,3/2)

PLEASE DON'T include 3/2 on the increasing interval because it's a turning point. The slope of the tangent line to the turning point is 0 so the graph isn't increasing OR decreasing at this point.

I really hope this helps!
Best wishes :)
7 0
3 years ago
Read 2 more answers
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