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Agata [3.3K]
3 years ago
9

Together Alex and Lily have 12 cats. If Alex has 3, write an equation to find out how many lily has.

Mathematics
2 answers:
zavuch27 [327]3 years ago
5 0

Answer:

12-3 lily has 9 cats

Step-by-step explanation:

nexus9112 [7]3 years ago
4 0

Answer:

9

Step-by-step explanation:

12 - 3 = 9

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Suppose that 5 J of work is needed to stretch a spring from its natural length of 36 cm to a length of 51 cm. (a) How much work
olganol [36]

Answer:

a) 0.6 joules of work are needed to stretch the spring from 41 centimeters to 46 centimeters.

b) The spring must be 5.6 centimeters far from its natural length.

Step-by-step explanation:

a) The work done to stretch the ideal spring from its natural length is defined by the following definition:

W = \frac{1}{2}\cdot k\cdot (x_{f}-x_{o})^{2} (1)

Where:

k - Spring constant, measured in newtons.

x_{o}, x_{f} - Initial and final lengths of the spring, measured in meters.

W - Work, measured in joules.

The spring constant is: (W = 5\,J, x_{o} = 0.36\,m, x_{f} = 0.51\,m)

k = \frac{2\cdot W}{(x_{f}-x_{o})^{2}}

k = \frac{2\cdot (5\,J)}{(0.51\,m-0.36\,m)^{2}}

k = 444.44\,\frac{N}{m}

If we know that k = 444.44\,\frac{N}{m}, x_{o} = 0.41\,m and x_{f} = 0.46\,m, then the work needed is:

W = \frac{1}{2}\cdot \left(444.44\,\frac{N}{m} \right)\cdot (0.46\,m-0.41\,m)^{2}

W = 0.555\,J

0.6 joules of work are needed to stretch the spring from 41 centimeters to 46 centimeters.

b) The elastic force of the ideal spring (F), measured in newtons, is defined by the following formula:

F = k\cdot \Delta x (2)

Where \Delta x is the linear difference from natural length, measured in meters.

If we know that k = 444.44\,\frac{N}{m} and F = 25\,N, then the linear difference is:

\Delta x = \frac{F}{k}

\Delta x = \frac{25\,N}{444.44\,\frac{N}{m} }

\Delta x = 0.056\,m

The spring must be 5.6 centimeters far from its natural length.

3 0
3 years ago
Please help me on this
Lina20 [59]
The answer is D since if a variable x was +4, then it is inverses to -4 and it would be reflected upon the vertical line, which happens to be the y axis
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3 years ago
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Vika [28.1K]

Answer:

equiangular -right -obtuse -acute.

5 0
2 years ago
The circumference of a circle is 15 centimeters. What is the diameter? Round to the nearest hundredths place.
lesya692 [45]

Answer:

4.77

Step-by-step explanation:

because Circumference can be found with this equation

C = 2piR

we need to plug in 15 for Circumference and solve for its radius or R.

15 = 2piR

15/2pi = R

but we need diameter which is 2R so we just need to multiply the answer by 2.

15/2pi × 2 = Diameter

15/pi = D

approximately = 4.77

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Which expression shows the result of applying the distributive property to −2(13x−15)−2(13x−15) ?
defon
D is the answer good luck

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