Answer:
1:1:1:1 walnut comb
Explanation:
If a cross is made between a female who is RRpp (rose comb) and a male who is rrPP (pea comb) then:
P: RRpp x rrPP
F1: RrPp RrPp RrPp RrPp
This means that all of the offspring in F1 generation will have heterozygous genotype (at both loci). Since it contains both dominant alleles, the phenotype is walnut comb.
(a) The alleles of white feathers and that of single-head combs are dominant while that of the dark feathers and small combs are recessive.
(b) 1/16 or 6.25%
<h3>Dihybrid crossing</h3>
Since all the offspring resemble their mother, it means the alleles that make up the traits of the mother are dominant over that of the father.
Assuming that:
Feathers color = F/f
Comb type = C/c
Genotype of mother = FFCC
Genotype of father = ffcc
FFCC x ffcc
FfCc
Crossing: FfCc x FfCc
Progeny
F_C_ = 9/16
ffC_ = 3/16
F_cc = 3/16
ffcc = 1/16
More on dihybrid crosses can be found here: brainly.com/question/1185199
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Answer:
elimination ingestion-digestion -absorption -elimination
