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2 years ago

Solve when G= -4/3 and h= 1/3 G+2h-3g-4h

Mathematics

1 answer:

Alexandra [31]2 years ago

8 0

Answer:

Step-by-step explanation:

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X + 2y = 5

Dafna11 [192]

B. 2
if any other number was in there i dont think it would work because its neg

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3 years ago

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(MC)

Juli2301 [7.4K]

Answer:

Square root 112 Units.

Step-by-step explanation:

See the image attached for the work.

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2 years ago

Consider F and C below. F(x, y, z) = yz i + xz j + (xy + 6z) k C is the line segment from (2, 0, −2) to (5, 4, 2) (a) Find a fun

WITCHER [35]

Answer:

Required solution (a) $f(x,y,z)=xyz+3z^2+C$ (b) 40.

Step-by-step explanation:

Given,

$F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k$

(a) Let,

$F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k=f_x \uvec{i} +f_y \uvex{j}+f_z\uvec{k}$

Then,

$f_x=yz,f_y=xz,f_z=xy+6z$

Integrating $f_x$ we get,

$f(x,y,z)=xyz+g(y,z)$

Differentiate this with respect to y we get,

$f_y=xz+g'(y,z)$

compairinfg with $f_y=xz$ of the given function we get,

$g'(y,z)=0\implies g(y,z)=0+h(z)\implies g(y,z)=h(z)$

Then,

$f(x,y,z)=xyz+h(z)$

Again differentiate with respect to z we get,

$f_z=xy+h'(z)=xy+6z$

on compairing we get,

$h'(z)=6z\implies h(z)=3z^2+C$ (By integrating h'(z)) where C is integration constant. Hence,

$f(x,y,z)=xyz+3z^2+C$

(b) Next, to find the itegration,

$\int_C \vec{F}.dr=\int_C \nabla f. d\vec{r}=f(5,4,2)-f(2,0,-2)=(52+C)-(12+C)=40$

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3 years ago

Given g(x) =<br> 1/4(15 – 2)<br> what is the value of g(7)?

umka2103 [35]

Answer:1234567890

Step-by-step explanation:101112131415161789995657

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2 years ago

An airline charges an extra fee if a suitcase weighs more than 50 pounds. After packing, Li's suitcase weighs 47.75 pounds. Whic

Vinvika [58]

Answer:

47.75 + x Less-than-or-equal-to 50

= 47.75 + x ≤ 50

Step-by-step explanation:

Solving the above Question:

Not going over the 50 pound case mean, less than or equal to 50 pounds

Let the extra pound of weight be represented as x

Hence, the inequality equation that can be used to determine how much more weight can be added to the suitcase without going over the 50-pound weight limit =

47.75 + x ≤ 50

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2 years ago

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