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OLEGan [10]
2 years ago
9

Solve when G= -4/3 and h= 1/3 G+2h-3g-4h

Mathematics
1 answer:
Alexandra [31]2 years ago
8 0

Answer:

2

Step-by-step explanation:

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Ahmed an Art dealer earns 25% commission of the dollar value of the art pieces that he sells at the Gallery. Ahmed earns $10,000
Mkey [24]

Answer:

$40,000

Step-by-step explanation:

25% of x = $10,000

0.25x = 10,000

x = 10,000/0.25

x = 40,000

Answer: $40,000

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7B2%7D%20%2B1%20%3D%20%5Csqrt%7B3%7D%20" id="TexFormula1" title=" \frac{x}{2
Tresset [83]
I hope this helps you

3 0
3 years ago
Help, 50 points
AnnyKZ [126]

Answer:

above is the solution to the question

5 0
2 years ago
Evaluate the surface integral ModifyingBelow Integral from nothing to nothing Integral from nothing to nothing With Upper S f (x
kykrilka [37]

Parameterize S by

\vec s(u,v)=6\cos u\sin v\,\vec\imath+6\sin u\sin v\,\vec\jmath+6\cos v\,\vec k

with 0\le u\le2\pi and 0\le v\le\frac\pi2. Take a normal vector to S,

\dfrac{\partial\vec s}{\partial v}\times\dfrac{\partial\vec s}{\partial u}=36\cos u\sin^2v\,\vec\imath+36\sin u\sin^2v\,\vec\jmath+36\cos v\sin v\,\vec k

which has norm

\left\|\dfrac{\partial\vec s}{\partial v}\times\dfrac{\partial\vec s}{\partial u}\right\|=36\sin v

Then the integral of f(x,y,z)=x^2+y^2 over S is

\displaystyle\iint_Sx^2+y^2\,\mathrm dS=\iint_S\left((6\cos u\sin v)^2+(6\sin u\sin v)^2\right)\left\|\frac{\partial\vec s}{\partial v}\times\frac{\partial\vec s}{\partial u}\right\|\,\mathrm du\,\mathrm dv

=\displaystyle36^2\int_0^{\pi/2}\int_0^{2\pi}\sin^3v\,\mathrm du\,\mathrm dv=\boxed{1728\pi}

6 0
3 years ago
Ahhhh i need help again.
qwelly [4]

Answer:

B

Step-by-step explanation:

A. these simply to 21 + 7x and 21 + 3x

  • this one is incorrect because the 7x and 3x are different

B. these simplify to 10 + x and 10 + x

  • this is the correct one since they are exactly the same

C. these simplify to 21x and 7x + 21

  • these two are not the same because one expression has only a number with a variable but the other one has a number with a variable <em>and </em>another number

D. these simplify to  \frac{7}{3-x}  and  \frac{7}{x-3}

  • in subtraction, the order of the 3 and the x matters, so the equations are not the same
  • example: 6 - 4 = 2 but 4 - 6 = -2
3 0
2 years ago
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