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3 years ago

3^4+4.5= Input whole number

Mathematics

2 answers:

Nina [5.8K]3 years ago

7 0

Step-by-step explanation:

<h2>MARK ME AS BRAINLIST</h2><h2>PLZ FOLLOW ME</h2>

Rasek [7]3 years ago

3 0

Answer:

thats 86 because it's the nearest whole number

Step-by-step explanation:

(3 × 3 × 3 × 3) + 4.5

81 + 4.5

85.5

<h2><em><u>SO THAT MEANS 3^4+4.5 = 85.5 rounded to the nearest whole number is 86</u></em></h2>

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2 years ago

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mixas84 [53]

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Step-by-step explanation:

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2 years ago

A lift driver charges $5.25 for the first mile of the trip and$1.25 each mile after that. He charges the customer $24 for the ri

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3 years ago

Read 2 more answers

The projected rate of increase in enrollment at a new branch of the UT-system is estimated by E ′ (t) = 12000(t + 9)−3/2 where E

nexus9112 [7]

Answer:

The projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

Step-by-step explanation:

Consider the provided projected rate.

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Integrate the above function.

$E(t) =\int 12000(t + 9)^{\frac{-3}{2}}dt$

$E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+c$

The initial enrollment is 2000, that means at t=0 the value of E(t)=2000.

$2000=-\frac{24000}{\left(0+9\right)^{\frac{1}{2}}}+c$

$2000=-\frac{24000}{3}+c$

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Therefore, $E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

Now we need to find $\lim_{t \to \infty} E(t)$

$\lim_{t \to \infty} E(t)=-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

$\lim_{t \to \infty} E(t)=10,000$

Hence, the projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

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3 years ago

Find two numbers a and b whose sum a+b is −1, and whose difference a−b is 1.

fiasKO [112]

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