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3 years ago

Find the correct sum of the polynomials (6x3 − 8x − 5) + (3x3 + 6x + 2).

Mathematics

1 answer:

Advocard [28]3 years ago

3 0

Answer:

$9x^3-2x-3$

Step-by-step explanation:

The question is

$(6x^3-8x-5)+(3x^3+6x+2)\\$

collect like terms

$(6x^3-8x-5)+(3x^3+6x+2)\\\\\\6x^3+3x^3-8x+6x-5+2\\\\\\9x^3-2x-3$

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3 years ago

What is the area of a circular region whose diameter is 10 centimeters?

stepan [7]

Answer:

78cm

Step-by-step explanation:

d = 10

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3 years ago

Use the Law of Cosines to find the values of x and y. (PLEASE HELPPP!!!!)

vredina [299]

Answer:

$x = 49.8^\circ\\y = 54.6^\circ$

Step-by-step explanation:

Kindly refer to the image attached in the answer region for labeling of triangle.

AB = 16

BC = 19

AC = 15

$\angle ABC = x^\circ\\\angle ACB = y^\circ$

We have to find the angles x and y i.e. $\angle B \text{ and }\angle C$ .

Formula for cosine rule:

$cos B = \dfrac{a^{2}+c^{2}-b^{2}}{2ac}$

Where

a is the side opposite to $\angle A$ ,

b is the side opposite to $\angle B$ and

c is the side opposite to $\angle C$ .

$\Rightarrow cos x = \dfrac{19^{2}+16^{2}-15^{2}}{2 \times 19 \times 16}\\\Rightarrow cos x = \dfrac{392}{608} \\\Rightarrow x = 49.8^\circ$

Similarly, for finding the value of y:

$cos C = \dfrac{a^{2}+b^{2}-c^{2}}{2ab}\\\Rightarrow cos y = \dfrac{19^{2}+15^{2}-16^{2}}{2 \times 19 \times 15}\\\Rightarrow cos y = \dfrac{330}{570}\\\Rightarrow y = 54.6^\circ$

Hence, the values are:

$x = 49.8^\circ\\y = 54.6^\circ$

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3 years ago

Where is mean by g(x)

matrenka [14]

Answer:

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