What is the solution set of x2 + y2 = 26 and x − y = 6? A. {(5, -1), (-5, 1)} B. {(1, 5), (5, 1)} C. {(-1, 5), (1, -5)} D. {(5,
Rus_ich [418]
He two equations given are
x^2 + y^2 = 26
And
x - y = 6
x = y +6
Putting the value of x from the second equation to the first equation, we get
x^2 + y^2 = 26
(y + 6) ^2 + y^2 = 26
y^2 + 12y + 36 + y^2 = 26
2y^2 + 12y + 36 - 26 = 0
2y^2 + 12y + 10 = 0
y^2 + 6y + 5 = 0
y^2 + y + 5y + 5 = 0
y(y + 1) + 5 ( y + 1) = 0
(y + 1)(y + 5) = 0
Then
y + 1 = 0
y = -1
so x - y = 6
x + 1 = 6
x = 5
Or
y + 5 = 0
y = - 5
Again x = 1
So the solutions would be (-1, 5), (1 , -5). The correct option is option "C".
Yes, your current answer is correct. Divide each term by the divisor.
Answer:
7 × 1/5
Step-by-step explanation:
hope this helps
7 × 1/5= 1.40
Answer:
option 3.75°
Step-by-step explanation:
we know that
If two triangles are similar, then the corresponding angles are congruent
so
In this problem
The corresponding angles are
m∠A and m∠D, m∠B and m∠E, m∠C and m∠F
so
m∠A=m∠D
m∠B=m∠E
m∠C=m∠F
therefore
m∠F=75°
