All categories

4 years ago

Answer that question please <3

Mathematics

1 answer:

GaryK [48]4 years ago

5 0

The answer is going to be D

You might be interested in

Evaluate this expression.<br> 8x, if x = 6

grandymaker [24]

Answer:

Step-by-step explanation:

8 times 6 = 48

5 0

3 years ago

Read 2 more answers

A coin contains 1.25, point grams of nickel and 3.75, point, grams of copper, for a total weight of 5 grams. What percentage of

jarptica [38.1K]

3.75 grams of copper / 5 total grams =

.75 = 75%

8 0

4 years ago

Find ( f o g) (x) when f (x) = x^2+6x+5 and g(x)=1/x+1

olchik [2.2K]

Answer:

$(f\circ g)(x)=\frac{1}{x^{2}}+\frac{8}{x}+12$

Step-by-step explanation:

Given that $f (x) = x^{2}+6x+5$ and $g(x)=\frac{1}{x}+1$ are the functions.

To find $(f\circ g)(x)$ with the given two functions. ie., to find the composite function of f(x) and g(x) which is denoted by $(f\circ g)(x)$

$(f\circ g)(x)=f(g(x))$

$=f(\frac{1}{x}+1)$

$=({\frac{1}{x}+1})^{2}+6\times ({\frac{1}{x}+1})+5$

$=\frac{1}{x^{2}}+\frac{2}{x}+1+\frac{6}{x}+6+5$

$=\frac{1}{x^{2}}+\frac{8}{x}+12$

Therefore $(f\circ g)(x)=\frac{1}{x^{2}}+\frac{8}{x}+12$

Therefore the composite function of f(x) and g(x) is $(f\circ g)(x)=\frac{1}{x^{2}}+\frac{8}{x}+12$

7 0

4 years ago

During their first home game, the Eagles soccer team drew a total of 176 fans. By the second game, this number grew to 202 fans.

vazorg [7]

Answer:

Step-by-step explanation:

Initial # = 176 fans

Final # = 202 fans

Increase = 202 - 176 = 26 fans

% increase = 100% x (Increase / initial #)

= 100 x (26/176)

= 100 x 0.1477

= 14.78%

5 0

3 years ago

The time to complete an exam is approximately Normal with a mean of 70 minutes and a standard deviation of 10 minutes. Using the

MatroZZZ [7]

Answer:

16% of students will complete the exam in less than 60 minutes

Step-by-step explanation:

The Empirical Rule(68-95-99.7) states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 70

Standard deviation = 10

What percentage of students will complete the exam in less than 60 minutes

60 = 70-10

So 60 is one standard deviation below the mean

By the Empirical Rule, 68% of the measures are within 1 standard deviation of the mean, that is, from 60 to 80 minutes. The other 100-68 = 32% is outside this interval. Since the normal distribution is symmetric, 16% of those are below 60 and 16% of those are above 80.

16% of students will complete the exam in less than 60 minutes

5 0

3 years ago