Question

If the radius of the base of the cone, r, is 8/3 units and the height, h, is 13 units, what is the volume of the cone?

Answer 1

Question:-

If the radius of the base of the cone, r, is $\frac{8}{3}$ units and the height, h, is 13 units, what is the volume of the cone ?

Answer:-

Given:-

$\bullet$ Radius of the base of the cone (r) is $\frac{8}{3}$ units.

$\bullet$ Height (h) of the cone is 13 units.

To Find:-

Volume of the cone.

Solution:-

We know,

Formula of volume of cone is $\frac{1}{3}$ πr²h

So, volume of the cone = $\frac{1}{3}$ × $\frac{22}{7}$ × $(\frac{8}{3})²$ × 13

= $\frac{1}{3}$ × $\frac{22}{7}$ × $\frac{8}{3}$ × $\frac{8}{3}$ × 13

= $\frac{22 \: × \: 8 \: × \: 8 \: × \: 13}{3 \: × \: 7 \: × \: 3 \: × \: 3}$

= $\frac{18304}{189}$

= 96.85 cubic units.

Volume of the cone is 96.85 cubic units. [Answer]

Answer 2

Answer:

Step-by-step explanation:

r = 8/3 units

h = 13 units

Volume of cone = (1/3) πr²h

                           $= \frac{1}{3}* 3.14 * \frac{8}{3}* \frac{8}{3}*13\\\\= 96.76 cubic units$