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3 years ago

Help help help please

Mathematics

1 answer:

AURORKA [14]3 years ago

8 0

Answer:

I did this assignment earlier the answer is All Real Numbers.

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Nvm bro i got the answer

KIM [24]

Ok and have a nice day

6 0

2 years ago

2/3+1/2 HURRY I NED IT ANSWERED ASAP

Sunny_sXe [5.5K]

Answer:

1 1/6 pls vote branliest

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

2 1/2 divided by 1 5/8? I forgot how to divide fractions and simplify them....please help

nlexa [21]

$2\frac{1}{2}:1\frac{5}{8}=\frac{2\times2+1}{2}:\frac{1\times8+5}{8}=\frac{5}{2}:\frac{13}{8}=\frac{5}{\not2_1}\times\frac{\not8^4}{13}=\frac{5}{1}\times\frac{4}{13}=\frac{5\times4}{1\times13}=\frac{20}{13}=1\frac{7}{13}$

3 0

3 years ago

Read 2 more answers

2. What percent of rolling a 2 3 probability of getting HH

faust18 [17]

Answer:

2. The correct answer option is 25%.

3. The experimental probability is 3% greater than the theoretical probability.

Step-by-step explanation:

2. We are given that a number cube is rolled 20 times out of which 5 times it lands on the number 2.

We are to find the experimental probability of getting the number 2.

P (2) = $\frac{5}{20} \times 100 =\frac{1}{4} \times 100$ = 25%

3. The theoretical Outcomes are: HH HT TH TT

So theoretical probability of getting HH = $\frac{1}{4} \times 100$ = 25%

Total number of outcomes = $28+22+34+16$ = 100

So experimental probability of getting HH = $\frac{28}{100} \times 100$ = 28%

Therefore, the experimental probability is 3% greater than the theoretical probability.

6 0

3 years ago

From a piece of tin in the shape of a square 6 inches on a side, the largest possible circle is cut out. What is the ratio of th

wel

Answer:

$\sf \dfrac{1}{4} \pi \quad or \quad \dfrac{7}{9}$

Step-by-step explanation:

The width of a square is its side length.

The width of a circle is its diameter.

Therefore, the largest possible circle that can be cut out from a square is a circle whose diameter is equal in length to the side length of the square.

Formulas

$\sf \textsf{Area of a square}=s^2 \quad \textsf{(where s is the side length)}$

$\sf \textsf{Area of a circle}=\pi r^2 \quad \textsf{(where r is the radius)}$

$\sf \textsf{Radius of a circle}=\dfrac{1}{2}d \quad \textsf{(where d is the diameter)}$

If the diameter is equal to the side length of the square, then:
$\implies \sf r=\dfrac{1}{2}s$

Therefore:

$\begin{aligned}\implies \sf Area\:of\:circle & = \sf \pi \left(\dfrac{s}{2}\right)^2\\& = \sf \pi \left(\dfrac{s^2}{4}\right)\\& = \sf \dfrac{1}{4}\pi s^2 \end{aligned}$