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salantis [7]
3 years ago
12

Construct a rectangle with side 6cm and 4.5cm?​

Mathematics
1 answer:
Darina [25.2K]3 years ago
8 0
Construct a rectangle with the sides 6cm and 4.5cm☹️☹️☹️ no answer
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A cone has a radius of 200 m at its base. The cone is 50 m high. How much space is inside the cone?
Sauron [17]

The question "how much space is inside a solid?" is actually asking about the volume of that solid.

The volume of a cone is given by

V = \dfrac{1}{3}\pi hr^2

where h is the height of the cone, and r is its radius.

So, you only need to plug in the values:

V = \dfrac{1}{3}\pi\cdot 50 \cdot 200^2 = \dfrac{2000000\pi}{3}m^3

7 0
3 years ago
Truck holds 2 1/4 tons. Loader outs 750 pounds in a truck at a time. How many loads till truck is full
iragen [17]
7 Loads , Hope this helps
4 0
3 years ago
The median and mean of these numbers:
aleksandr82 [10.1K]

Answer:

Mean : ≈ 12.7

Median: ≈ 13.5

Step-by-step explanation:

To find the mean you must add all the numbers and divide by the # of numbers in the set.

8+12+13+14+14+15 = 76

76/6 ≈ 12.7

To find the median you have to order the numbers from least to greatest, the middle number should be the median, but in this case two numbers are in the middle.

8, 12, 13, 14, 14, 15

So you have to add 14 and 13, which is 27.

Then divide by 2 which is ≈ 13.5

8 0
3 years ago
3⋅ (3⁴) = 3x=<br> What does x equal to?
sergeinik [125]
X=27
81 = 3x= 27
So x means 27
6 0
3 years ago
Solve for x.<br><br> 5/6 x = 10/3<br><br> x = 4/3<br><br> x = 2<br><br> x = 25/9<br><br> x = 4
SashulF [63]

Answer: LAST OPTION.

Step-by-step explanation:

In order to solve for the variable "x" from the expression \frac{5}{6}x=\frac{10}{3}, you need to follow these steps:

1) You need to multiply both sides of the equation by 3:

3(\frac{5}{6}x)=(\frac{10}{3})(3)\\\\\frac{15}{6}x=10

2)  You need to multiply both sides of the equation by 6:

(6)(\frac{15}{6}x)=(10)(6)\\\\15x=60

3) Finally, you can divide both sides of the equation by 15:

\frac{15x}{15}=\frac{60}{15}\\\\x=4

4 0
4 years ago
Read 2 more answers
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