So, f[x] = 1/4x^2 - 1/2Ln(x)
<span>thus f'[x] = 1/4*2x - 1/2*(1/x) = x/2 - 1/2x </span>
<span>thus f'[x]^2 = (x^2)/4 - 2*(x/2)*(1/2x) + 1/(4x^2) = (x^2)/4 - 1/2 + 1/(4x^2) </span>
<span>thus f'[x]^2 + 1 = (x^2)/4 + 1/2 + 1/(4x^2) = (x/2 + 1/2x)^2 </span>
<span>thus Sqrt[...] = (x/2 + 1/2x) </span>
The way you have it is correct because root 2 is roughly 1.4 pi approximately is 3.4 and 4.5 is a rational number
There are 100 pennies in a dollar. We can divide 12000 pennies by 100 to find out how much they are worth in dollars.
12000/100 = $120
Answer:
Yes. Intergers are all whole numbers so negative whole numbers are included too.
Step-by-step explanation:
