Usually one will differentiate the function to find the minimum/maximum point, but in this case differentiating yields:

which contains multiple solution if one tries to solve for x when the differentiated form is 0.
I would, though, venture a guess that the minimum value would be (approaching) 5, since the function would be undefined in the vicinity.
If, however, the function is

Then differentiating and equating to 0 yields:

which gives:

or

We reject x=5 as it is when it ix the maximum and thus,

, for
Answer:
slope = 35; y-intercept = -45
Step-by-step explanation:
Function f(x) is written in the slope-intercept form, y = mx + b.
f(x) = -7x + 9
You compare it with
f(x) = mx + b, and you see that m, the slope, is -7, and b, the y-intercept is 9.
Now we deal with function h(x).
h(x) = -5(-7x + 9)
This is not written in the y = mx + b form, but we can put it in that form by distributing the -5.
h(x) = 35x - 45
Now, h(x) is written in the y = mx + b form. We see clearly that m = 35, so the slope of function h is 35. We also see that b, the y-intercept is -45.
Answer: slope = 35; y-intercept = -45
Answer:
The correct option is D. y = 25
.
Step-by-step explanation:
i) From the table and our own observation and a trial and error approach we
can clearly see that the equation that matches y in feet ( the distance
traveled by the rocket) and x in seconds ( the time elapsed) is given by the
equation y = 25
Therefore the correct option is D. y = 25
.
A number 4 times as much as 25 is 100