Solve.<br><br> −<br> 2<br> 5<br> x<br> −<br> 9<br> <<br> 9<br> 10

Name the angle that is supplementary to< COB PLease help me if you do I will give you brainly!!!

yarga [219]

Answer:

<BOF is the right answer.

Step-by-step explanation:

The other ones only give one side and you need it to be the whole angle.

7 0

3 years ago

Math help please show work thanks

GalinKa [24]

Problem 5

d = 29 = diameter

r = d/2 = 29/2 = 14.5 = radius

SA = surface area of sphere

SA = 4*pi*r^2

SA = 4*pi*(14.5)^2

SA = 841pi

SA = 841*3.14

SA = 2,640.74 square inches

To convert from square inches to square feet, we divide by 144. This is because 12^2 = 144.

2,640.74 square inches = (2,640.74)/144 = 18.3 sq ft

<h3>Answer: 18.3 square feet (approximate)</h3>

=====================================

Problem 6

d = 10.7 = diameter

r = d/2 = 10.7/2 = 5.35 = radius

L = 22.3 = slant height

SA = surface area of the cone

SA = pi*r^2 + pi*r*L

SA = pi*(5.35)^2 + pi*5.35*22.3

SA = 147.9275pi

SA = 147.9275*3.14

SA = 464.49235

<h3>Answer: 464.49235 square cm (approximate)</h3>

8 0

3 years ago

what is the length of tw¯¯¯¯¯¯ ? segment t w with point u between t and w. segment t u is marked congruent to segment u w. segme

Gennadij [26K]

T________U________W
16
TU=UW
16=16
TW=TU+UW
TW=16+16
TW=32

6 0

3 years ago

Read 2 more answers

Use the given information to find the exact value of the trigonometric function

eimsori [14]

$\begin{gathered} \csc \theta=-\frac{6}{5} \\ \tan \theta>0 \\ \cos \frac{\theta}{2}=\text{?} \end{gathered}$

Half Angle Formula

$\cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}}$ $\tan \theta>0\text{ and csc}\theta\text{ is negative in the third quadrant}$ $\begin{gathered} \csc \theta=-\frac{6}{5}=\frac{r}{y} \\ x^2+y^2=r^2 \\ x=\pm\sqrt[\square]{r^2-y^2} \\ x=\pm\sqrt[\square]{6^2-(-5)^2} \\ x=\pm\sqrt[\square]{36-25} \\ x=\pm\sqrt[\square]{11} \\ \text{x is negative since the angle is on the 3rd quadrant} \end{gathered}$ $\begin{gathered} \cos \theta=\frac{x}{r}=\frac{-\sqrt[\square]{11}}{6} \\ \cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}} \\ \cos \frac{\theta}{2}is\text{ also negative in the 3rd quadrant} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{1+\frac{-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{\frac{6-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}} \\ \\ \end{gathered}$

Answer:

$\cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}$

Checking:

$\begin{gathered} \frac{\theta}{2}=\cos ^{-1}(-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}) \\ \frac{\theta}{2}=118.22^{\circ} \\ \theta=236.44^{\circ}\text{ (3rd quadrant)} \end{gathered}$

Also,

$\csc \theta=\frac{1}{\sin\theta}=\frac{1}{\sin (236.44)}=-\frac{6}{5}\text{ QED}$

The answer is none of the choices

7 0

1 year ago

Please help me with this

Vera_Pavlovna [14]

Answer:

226.19

Step-by-step explanation:

pi * r^2 = area

The radius = diameter/2 = 6

pi * 6^2 * 2 = area of 2 tortillas

72pi = area of 2 tortillas

That rounds to 226.19

3 0

3 years ago

Solve. − 2 5 x − 9 < 9 10