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3 years ago

What will most banks do about a bounced check?

Mathematics

1 answer:

Arisa [49]3 years ago

7 0

The first one, return your check

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Which equation is a linear function? y=2^x -1 y=x/2-5 y=2/x +3 y=x^2 +7

Umnica [9.8K]

Answer:

Second Choice.

Step-by-step explanation:

$y = mx + b$

That is the linear function. Any coefficients with higher degrees won't be considered as a linear function.

So we can cut out the first and last choice.

Then we have only two choices which are

$y = \frac{x}{2} - 5 \\ y = \frac{2}{x} + 3$

The second equation is called Rational Function where a variable is a denominator.

Therefore, the correct answer is second choice.

5 0

3 years ago

Explain how you know 21/30 is greater than 2/3

Luba_88 [7]

Simple.

to figure out if they are either: equal, greater, or smaller...

First, find a common denominator...

$\frac{21}{30}$

and

$\frac{2}{3} * \frac{10}{10} = \frac{20}{30}$

Now, we can obviously make the assumption that $\frac{21}{30}$ is greater than $\frac{20}{30}$ .

Thus, your answer.

3 0

3 years ago

Read 2 more answers

Q12 A driver sees this speed limit sign in France. The speed is in kilometres per hour

olga nikolaevna [1]

Answer:

Step-by-step explanation: idk

7 0

4 years ago

Type the correct answer in the box. Round your answer to the nearest integer.

umka21 [38]

Answer:

m∠ADC = 132°

Step-by-step explanation:

From the figure attached,

By applying sine rule in ΔABD,

$\frac{\text{sin}(\angle ABD)}{\text{AD}}=\frac{\text{sin}(\angle ADB)}{AB}$

$\frac{\text{sin}(120)}{35}=\frac{\text{sin}(\angle ADB)}{30}$

sin(∠ADB) = $\frac{30\text{sin}(120)}{35}$

= 0.74231

m∠ADB = $\text{sin}^{-1}(0.74231)$

= 47.92°

≈ 48°

m∠ADC + m∠ADB = 180° [Linear pair of angles]

m∠ADC + 48° = 180°

m∠ADC = 180° - 48°

m∠ADC = 132°

4 0

3 years ago

Simplify completely the quantity 4 times x to the third power plus 5 times x to the 2nd power plus 3 times x all over x. (2 poin

ikadub [295]

Answer: 4x² + 5x + 3

Step-by-step explanation:

$\dfrac{4x^3+5x^2+3x}{x}\\\\\\=\dfrac{x(4x^2+5x+3)}{x}\qquad \text{factored out the common term from the numerator}\\\\\\=4x^2+5x+3\qquad \text{canceled out x from numerator and denominator}$

8 0

4 years ago